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Old 17th November 2010, 01:29 AM   #1
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Default What impedance is this setup?

I have one cabinet that has 4 - 16 ohm speakers, wired into series-parallel. If I add a second single speaker cabinet, how does this impedance change? There are 2 photos of possible ways to hook up. One would put the cabinets in parallel and one in series.

The big question is this, since the 4 - 16 ohm cabinet comes down to 16 ohms total, would this act as one 16 ohm driver or would it act strangely if I added another cabinet??



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Last edited by Rotus623; 17th November 2010 at 01:31 AM.
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Old 17th November 2010, 02:05 AM   #2
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total impedance of parallel connection is 8 ohms, of series connection 32 ohms, either way power would be shared evenly by the quad box and the single speaker; whether it's worthwhile would depend on their relative efficiencies.
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Impedance varies with frequency, use impedance plots of your drivers and make crossover calculations using the actual impedance of the driver at the crossover frequency
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Old 17th November 2010, 02:07 AM   #3
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Quote:
Originally Posted by PeteMcK View Post
total impedance of parallel connection is 8 ohms, of series connection 32 ohms, either way power would be shared evenly by the quad box and the single speaker; whether it's worthwhile would depend on their relative efficiencies.
Cool, thanks Pete McKay, that is what I thought.
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