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#1 |
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diyAudio Member
Join Date: Dec 2005
Location: west lafayette
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It would be trivial to calculate the motion of a pendulum if displacement is assumed small and if an infinitely rigid rod is assumed to connect the boundary and the mass.
Satisfying the first assumption is easy. All we have to do is maximize the mass ratio. However, we cannot easily satisfy the second assumption. In fact, it would probably be better if we used something similar to a frictionless string. #1 Aesthetics aside, what would you consider to be the ideal material that approaches the behavior of a "frictionless" string? #2 I assume the string will have resonances (I think this is why StigErik chose to use rubber for his material). How would you calculate this? The boundary condition does not equal zero. Would that make it an inhomogeneous differential equation? #3 How would the equations change if a 3D swing (ie you might visualize it as a tripod that is inverted and whose rods are replaced by strings) compared to a swing with a single string? #4 What would you consider to be the minimum mass ratio? It would appear that the displacement of the pendulum would have a negligible effect on the response of the loudspeaker, UNLESS its displacement approached the dimensions of the highest reproduced wavelength. Would you consider 1/(highest reproduced wavelength*10) to be a good rule of thumb for maximum allowable displacement of the pendulum? Thanks, Thadman
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"It is a profound and necessary truth that the deep things in science are not found because they are useful; they are found because it was possible to find them." Last edited by thadman; 11th November 2010 at 10:27 PM. |
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#2 |
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diyAudio Member
Join Date: Jun 2005
Location: Taiwan
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I think the key is "a simple pendulum".
So, A, B, C are all good, D is not. Other than that (and if the string itself is light enough), I don't worry about the friction or resonance. After all, the energy transfered by the stings is so little. |
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#3 |
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diyAudio Member
Join Date: Jun 2009
Location: Orygun
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#4 | |
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diyAudio Member
Join Date: May 2004
Location: Pensacola, Florida
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Quote:
Regards, WHG Last edited by whgeiger; 12th November 2010 at 02:05 PM. Reason: Typo |
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#5 |
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diyAudio Member
Join Date: Jun 2009
Location: Orygun
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#6 |
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diyAudio Member
Join Date: Sep 2002
Location: Lakewood, Ohio
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On string:
1/8 inch (3mm) diameter rope is readily available with a tensile strength of 2600 pounds! But it costs over $1.25 per foot.
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Kevin |
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#7 |
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Account disabled at member's request
Join Date: Feb 2002
Location: Clifton Park, NY
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I think the biggest problem faced by these driver suspended by a "thin" wire (string, rope, chain, cable ..... whatever) designs is that you have now turned the driver into a two degree of freedom system with the suspension wires being the path to ground. The driver cone and voice coil is mass one, the surround is spring one, the driver frame is mass two, and the suspension wires to ground are spring two. The first mode will be the cone and frame moving together stretching both of the springs, the second mode will be the cone moving forward the frame will moving backward (I can't believe that is a good result). One mode will be below and one above fs. A massive stiff baffle rigidly coupled to the driver frame and the floor forces the driver to act as a single degree of freedom system as intended.
I saw this when testing my 18" Goldwood H frame design. I had the speaker sitting on my garage floor and was measuring the voice coil electrical impedance. So the small signal oscillating cone was being reacted by the driver frame attached to the plywood H frame, seemed like a simple test at first. I was surprised to get two impedance peaks that bracketed the driver's fs. When I added mass to the H frame, I sat on it, I measured the impedance again and got only one peak as expected at the driver fs. In the first test the second mode of the H frame system was the driver cone moving one way and the H frame moving the opposite way (similar to subs that march across the floor). Think about the physics, if you suspend the driver by wires it will be a lumped mass suspended by wires. It will behave like a stretched string with a mass in the middle and have a resonant frequency. The higher the tension the higher the frequency, just like a violin string. This is why I am not a proponent of nude drivers hung by tension links or of magnet mounting a driver. The ultimate method for making the vibrating cone the only vibrating source of sound is by coupling a strong driver frame to a relatively rigid and massive open baffle. Martin |
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#8 |
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diyAudio Member
Join Date: Jun 2009
Location: Orygun
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Umm, to the extent there's any springiness in the lines (not much) the forces in a typical hang are normal to it (to an excellent approximation). So I'm not finding a way to apply the above analysis; I'm not aware of any cases where the driver ends up bouncing up and down.
I do agree infinite mass is one option in the design continuum but there's a fair bit of objective and subjective data to indicate swung or magnet mounted drivers are often better than baffle mounting---the measurements I've done are no exception. Martin, did you measure any decoupling techniques in addition to looking at the high mass end of the design continuum? Stig Erik's approach of sitting the H baffle on an inflated bicycle inner tube is an easy one to try. Also, what happened with SPL, phase, and linearity of the output sound with the second peak? |
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#9 | |
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diyAudio Member
Join Date: May 2004
Location: Pensacola, Florida
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Quote:
Regards, WHG |
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#10 |
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diyAudio Member
Join Date: Jun 2009
Location: Orygun
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Yeah. I agree with Martin that having the basket and magnet move in reaction to the cone isn't ideal. But with most drivers having cone:rest of driver mass ratios of 1:100 or more the reaction motion's minimal. Basket structures more or less have to have lower Sd and higher dipole peaks than the cone, but that's not the case for the magnet or spider---generally, the smaller the driver the larger and more efficient the magnet and spider are relative to the cone. However, for the woofers I've looked at the mass ratio tends to increase, offsetting that somewhat. So, in rough numbers, the SPL of the opposing wave from the basket and magnet is at most 45 or 50dB down from the wave off the cone. To the extent the phase shift induced by time of flight is small, this is a negligible reduction in SPL. For the commonly chosen six inch midwoofers the phase shift's around 45 degrees at the dipole peak which could, in principle, produce distortion terms around -50dB. That's below the ambient noise floor of most measurements so it's tough to pin down---I've poked around a bit with my eight inches and not been able to spot any issues.
As to the pendulum lines themselves, their Sd is small, dipole peak high, and resonant Q usually low. So getting them to voice like instrument strings is tough; I've not hit problems with that either. The point passive crossovers can suffer from impedance matching problems from mechanical coupling is interesting. I switched to active years ago so it's not something I've ever looked at. I would surmise, however, that reducing coupled mass by getting rid of the baffle works to mitigate the problem much like adding mass does. And there's a considerable evidence lowering the suspension resonance and Q also works. |
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