|Multi-Way Conventional loudspeakers with crossovers|
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|26th January 2010, 06:07 PM||#1|
Join Date: Jan 2010
trying to work out ohms on cabinet build
Great forum you have here
hopefully this will be a good first post..
Ok ive been looking at a cabinet that im trying to replicate but im struggling to under how the ohms law is working i'll try and explain
the cabinet has a 8 ohm impedance
the bit i dont understand is the fact that the components are as follows
15" 350wrms driver 8ohms
compression driver 8ohm
crossover for use with 8ohms
now as i understand if you wire 2 x 8 ohm speakers in parallel you make 4 ohms
and if you wire in series you would get 16 ohms
so how have they come up with a total impedance of 8 ohms
is it because the use of the crossover
|26th January 2010, 07:01 PM||#2|
Join Date: Feb 2008
Ok - there's a few reasons, so I'll try to cover them all.
The first is that it's considered 8 ohm nominal impedance. It's a number that's vaguely central to the impedance curve of the speaker. They're usually 4 or 8 ohm, so most will round to the nearest of those two.
The second reason is that a crossover is designed so that the drivers don't end up playing the same thing. Because of this, the impedances don't actually interract at all.
So, if you have a woofer of 8 ohm, cross it over to a tweeter of 8ohm, they will have no effect on one another. An easier way to think about it - picture 2 amps, on running the woofer, one running the tweeter. They'll each see 8ohm.
The problems occur when more than one driver is playing the same frequency range. Putting 2 8ohm woofers in parallel will indeed give 4 ohm.
Hope this helps
PS - Welcome to the forums.
"If you underspecify some resistors they can add extra phlogiston to the music mix. This gives a much more dramatic effect than refulgence, however superb it may be. Phlogiston can move a listener in a way that ordinary music cannot." - DF96
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