Power response - how do you calculate?

jzagaja · 30th September 2009, 01:42 PM

How do you calculate power response? It is extremely important for modal loudspeakers that have strong 3rd or 4th mode at around 10-15kHz and flat power response so that this resonance is not audible!

nullspace · 30th September 2009, 03:19 PM

Excellent question, and I too would like to know the answer.

Regards,
John

jzagaja · 30th September 2009, 03:49 PM

Maybe like that.

jzagaja · 1st October 2009, 08:32 AM

I see axisymetric source requires integral K^2(angle)*sin(angle)*d_angle, where K is directivity function. Non-axisymetric double integral with second angle. So that's the problem we need divide measured pressure by this integral? How to do this?

jzagaja · 23rd October 2009, 08:17 AM

Comparison between unbaffled Tangband W4-1798S and Balanced Mode Radiator - baffled and unbaffled. Baffled is power response and unbaffled is power average = sqrt(x1*x1+x2*x2)/2.

john k... · 23rd October 2009, 10:37 AM

Power response link

jzagaja · 23rd October 2009, 11:50 AM

John, does it explain how having omni microphone? I can't see

30th September 2009, 01:42 PM	#1
jzagaja diyAudio Member Join Date: Jun 2004 Location: Szczecin	Power response - how do you calculate? How do you calculate power response? It is extremely important for modal loudspeakers that have strong 3rd or 4th mode at around 10-15kHz and flat power response so that this resonance is not audible!

23rd October 2009, 10:37 AM	#6
john k... diyAudio Member Join Date: Aug 2004 Location: US	Power response link __________________ John k.... Music and Design NaO Dipole Loudspeakers. "We have no right to assume that any physical laws exist, or if they have existed up to now, that will continue to exist in a similar manner in the future." Max Planck

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30th September 2009, 03:19 PM	#2
nullspace diyAudio Member Join Date: Oct 2004 Location: Phila., PA	Excellent question, and I too would like to know the answer. Regards, John

1st October 2009, 08:32 AM	#4
jzagaja diyAudio Member Join Date: Jun 2004 Location: Szczecin	I see axisymetric source requires integral K^2(angle)sin(angle)d_angle, where K is directivity function. Non-axisymetric double integral with second angle. So that's the problem we need divide measured pressure by this integral? How to do this?

23rd October 2009, 11:50 AM	#7
jzagaja diyAudio Member Join Date: Jun 2004 Location: Szczecin	John, does it explain how having omni microphone? I can't see

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