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#1 |
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diyAudio Member
Join Date: Jul 2008
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Afternoon all, (well it is for me anyway!)
i want to use a pllxo to cross over to my sub (2nd order-80hz) im a little stuck though as i have my speakers tri-amped. using this guide-im stuffed as i dont know wha to put in as a value for the high pass amp impedence- can anyone help me? thanks people |
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#2 |
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diyAudio Member
Join Date: Jul 2008
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appologies- heres the guide http://www.t-linespeakers.org/tech/f...ssiveHLxo.html
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#3 |
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diyAudio Member
Join Date: Apr 2007
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May be that you'd feel uncomfortable with "big" capacitor values shunting to ground ?
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#4 | |
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diyAudio Member
Join Date: Jul 2008
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Quote:
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#5 |
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diyAudio Member
Join Date: Feb 2002
Location: Sydney
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if your 'R2' to ground is small enough, say 10K or less, the imput impedance is unlikely to have much effect...
(i.e. just make R1=R2)
__________________
‘today… there lives alongside the twentieth century the tenth or thirteenth. A hundred million people use electricity and still believe in the magic power of signs and exorcisms” Trotsky Last edited by PeteMcK; 25th September 2009 at 04:57 AM. |
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#6 |
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diyAudio Member
Join Date: Jun 2004
Location: KL
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May I know why C2=C1/10 and R2=10R1? Can I use like C1=C2 and R1=R2 since they will have the same -3dB frequency. Thanks.
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#7 |
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diyAudio Member
Join Date: Apr 2007
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Andrewwwww T ! Where are you ?
I think it's the Time Constant that had to be taken in consideration |
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#8 |
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diyAudio Member
Join Date: Feb 2002
Location: Sydney
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sorry guys, I was talking about the 1st order circuit,
R2 in the 2nd order schematic will be effected much more by the following input impedance if it's 10xR1 Ipanema, follow the link to Art Ludwig's site on the t-line speakers page link above if you want the gory details of the maths...
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‘today… there lives alongside the twentieth century the tenth or thirteenth. A hundred million people use electricity and still believe in the magic power of signs and exorcisms” Trotsky |
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#9 |
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diyAudio Member
Join Date: Jun 2004
Location: KL
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In the example given for second order filter with equation f=1/2*pi.*R*C,
f=1kHz: R1=5 k W, R2=50 k W, C1=31.8nF, C2=3.18nF and I will still get the same f even if C1=C2 and R1=R2, where f=1kHz: R1=5 k W, R2=5 k W, C1=31.8nF, C2=31.8nF I would appreciate if anyone can explain to me why Art Ludwig's prefer C2=C1/10 and R2=10R1. Thanks. Another note is the above equation is only accurate assuming that source output impedance is 0 and the stage after filter input impedance is infinity for HPF. |
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#10 | |
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frugal-phile(tm)
diyAudio Moderator
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Quote:
dave
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community sites t-linespeakers.org, frugal-horn.com ........ commercial site planet10-HiFi p10-hifi forum here at diyA |
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