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Old 29th May 2009, 09:21 PM   #1
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Default Trying to understand this LPF better

Hello all
I am trying to gain a better understanding of this basic LPF. In another tread is was described like this...

L1: 2.7 mH switchable to 3.6 and 2.0
L2: 500 uH (with 10 ohm parllel)
C1: 5 uF

Ok so I understand enough to see that L1, L2 and C1 make up a basic 18db LPF.

My main question would be what is the function of the ten Ohm resistor run in parallel with L2?

Thanks for any insight

EDIT: Ok ill take a guess... Is it a simple zobel to keep things more predictable?
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Old 29th May 2009, 11:27 PM   #2
Thawach is offline Thawach  Thailand
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the LPF filter to be added with Contour network.
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Old 30th May 2009, 12:17 AM   #3
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Thanks for the link.
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