Qts of Push-pull woofer and Compound Woofer System...
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 Multi-Way Conventional loudspeakers with crossovers

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 13th December 2001, 12:10 AM #1 haggy diyAudio Member   Join Date: Dec 2001 Location: Seoul Korea there are some equations. If there is any mistake, post reply please. fs=(1/2*3.14)*(Cms*Mms)^-1/2 so fs will be same. and, Qms=2*3.14*fs*(Mms/Cms) =(1/D)*(Mms/Cms)^1/2 so, I thought, D=Cms if this is right, in compound woofer system, Qms' is not same of single Qms. because Mms will be double, and Cms will be half because effective stiffness will be double. so, Qms'=(2/D)*(2*Mms/Cms/2)^1/2 =(2/D)*2*(Mms/Cms)^1/2 =4*(1/D)*(Mms/Cms)^1/2 =4*Qms and Qes=[Re/(Bl)^2]*(Mms/Cms)^1/2 I think l will be double and if my thinking is right, Bl will be double. and if wired in series, Re will be 2Re. so, Qes'=[2Re/(2Bl)^2]*(2Mms/Cms/2)^1/2 =2/4[Re/(Bl)^2]*2(Mms/Cms)^1/2 = Qes and, if wired in parallel, Re will be half. so Qes'=[(Re/2)/(2Bl)^2]*(2Mms/Cms/2)^1/2 =1/8[Re/(Bl)^2]*2(Mms/Cms)^1/2 = Qes/4 and Qts=Qms*Qes/(Qms+Qes) so I can't understand that push-pull or compound woofer system's Qts will be same of single driver. But that Qts of push-pull and compound woofer system is same og single driver is written on "the Loudspeaker Design Cookbook"(fifth edition by Vance Dickason) page 30 and 32 ! I'm very confused. please somebody help me....
 13th December 2001, 01:30 AM #2 hakalugi diyAudio Member   Join Date: Nov 2001 Location: DC please define... "push-pull" do you mean clamshell isobaric? like this: if so, i believe the only changes are: Vas, Impedence, Power handling.

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