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#1 |
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diyAudio Member
Join Date: Jan 2002
Location: Puget Sound
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I tried to search on this but the search engine says my search term contains too few characters.
I bought an MCM aluminum woofer before they changed their website. As a result, most of the T/S params are now missing. Because I want to build a transmission line enclosure, how do I get the Sd? Borrow the value from an 8" woofer whose value is known? |
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#2 |
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diyAudio Member
Join Date: Jan 2002
Location: Wellington, New Zealand
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Assuming a circular driver, sd can be approximated by an area calculation.
Measure the driver from the outer edge of the surround of one side, to the inner edge of the surround on the other side (diameter). (eg. the piston diameter is approximately half surrond to half surround) then sd is given by sd = ((0.5 * diameter) ^2) * pi (eg. circle area = pi * radius ^ 2) Dave. |
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#3 |
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diyAudio Member
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Not to be a stick in the mud but... when they refer to the area, wouldn't you want to approximate with a cone area, rather than a circle? Becuase the woofer is closer to cone-shaped than circular?
Or a paraboloid if it's like many car speakers are now? Or hyperbolic paraboloid if it's a hyperbolic paraboloid speaker? Or toroid if it's closer to a toroid shape? Or, will they be close enough together that it doesn't really matter that much? Or, is this a parameter that can be fudged in one direction and be just fine? Or, is this a parameter that, if you got it wrong, you can just change the stuffing to fix it? *devil's advocate* |
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#4 |
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diyAudio Member
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Basically, I think you will find that an 8" woofer has around 32 sq inches. A 10" has 56 sq inches, a 12" has 86 sq inches, and a 15" has 132 sq inches. These are approximations-it is very rare indeed that you need any exact figures, and besides, measuring methods vary.
PS: 32 sq in equals 200 sq cm.
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"A friend will help you move. A really good friend will help you move a body." -Anonymous |
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#5 |
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diyAudio Member
Join Date: Jan 2002
Location: Puget Sound
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Since the cone is supposed to operate as a piston, I don't think the actual surface area of the cone is as important. I've seen Sd defined as effective diaphram area. This leads me to believe it is the area occupied by the base of the cone.
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#6 |
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diyAudio Member
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Ultra:
You might be right. However, cone area rarely must be exact. The numbers I gave often are a bit on the optimistic side. For Transmission Line purposes, you can approximate.
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"A friend will help you move. A really good friend will help you move a body." -Anonymous |
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#7 |
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diyAudio Member
Join Date: Mar 2003
Location: germany
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meassure the diameter of the cone and ad one half of the rubber sourround. I suppose you won't need it more accurate.
As mentioned before, die cone has to operate as a perfect (ugh, I'm dreaming of this
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#8 |
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diyAudio Member
Join Date: Mar 2001
Location: Quebec City
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Since this is for a transmission line, you don't need the exact number because the stuffing will have a bigger influence then the Sd. An approximate value is enough.
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Imagination is more important than knowledge. knowledge is limited, imagination encircles the world. Albert Einstein FrankDIY's Audio Corner |
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#9 |
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diyAudio Member
Join Date: Jan 2003
Location: Toronto
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Just get the measurements for the area of the cone and the area from surround to surround and then compare to another 8" drivers sd . That should give you an idea as to what measurement they use.
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#10 | |
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frugal-phile(tm)
diyAudio Moderator
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Quote:
* it is convenient to use Sd to define the geometry in Martin King's worksheets but the Sd does not have to be accurate. dave
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