2.5-way crossover design

[Puppetnation]

Hi,
I'm building a pair of 2.5-way floorstanding speakers, sealed cabinet, each woofer with its own separate volume.

Cabinet is almost ready, except for the front baffle, now it's time to think at the preliminary crossover circuit.

I just want to know if calculating a normal 2-way circuit (with paralleled woofers, obvious) it's the correct working step, before thinking at the next inductor and other components for the 0.5 way.

Thanks

[sreten]

Originally posted by Puppetnation
Hi,
I'm building a pair of 2.5-way floorstanding speakers, sealed cabinet, each woofer with its own separate volume.

Cabinet is almost ready, except for the front baffle, now it's time to think at the preliminary crossover circuit.

I just want to know if calculating a normal 2-way circuit (with paralleled woofers, obvious) it's the correct working step, before thinking at the next inductor and other components for the 0.5 way.

Thanks

Hi,

No it is not. Its more like a normal 2 way that ignores
BSC with an extra driver added to implement the BSC.

Calculating a c/o ? sets the alarm bells ringing ......


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http://www.geocities.com/woove99/Spkrbldg/

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http://htguide.com/forum/forumdisplay.php4?f=39

/sreten.

[Puppetnation]

Originally posted by sreten
[Its more like a normal 2 way that ignores
BSC with an extra driver added to implement the BSC.

No parallelled woofers? I'm confused...

[sreten]

Hi,

At the c/o point mid to treble you only have one active bass/mid unit.

/sreten.

[Puppetnation]

Originally posted by sreten
Hi,

At the c/o point mid to treble you only have one active bass/mid unit.

/sreten.

Ok Sreten, but my question was different:
I'd like to know if it's correct to start with a normal 2-way crossover layout (with 2 paralleled midwoofers, so calculate the LP inductor for 2 paralleled speakers) and THEN thinking at the additional 0.5 way components and BSC...

In a few words, can I imagine a normal 2-way crossover with 2 par. woofers and -only later- working at the second woofer circuitry?

[sreten]

Hi,

Like I said no its not. If the 2 way c/o design ignores BSC then
the 2.5 way design is a single MT 2-way with an added 0.5 driver.

You cannot start with a paralled MTM type 2-way crossover that
ignores BSC and then move on to implementing 0.5 way BSC
with the same crossover components and a 0.5 way inductor.
This should be blindingly obvious ........

/sreten.

[bzfcocon]

I second that, starting with two paralleled woofers in a 2 way crossover and then adding a 0.5 way on one will obviously mess things at the crossover point.

Starting with one woofer in a 2 way crossover and then adding the 0.5 way woofer makes more sense, although there is still a possibility to mess things at the crossover if the 0.5way woofer has still some output - in the end, the overall response must be considered.

[Puppetnation]

Originally posted by sreten
Hi,

Like I said no its not. If the 2 way c/o design ignores BSC then
the 2.5 way design is a single MT 2-way with an added 0.5 driver.

You cannot start with a paralled MTM type 2-way crossover that
ignores BSC and then move on to implementing 0.5 way BSC
with the same crossover components and a 0.5 way inductor.
This should be blindingly obvious ........

/sreten.

Ok, it's clear now.

Thanks

[Puppetnation]

Originally posted by bzfcocon
I second that, starting with two paralleled woofers in a 2 way crossover and then adding a 0.5 way on one will obviously mess things at the crossover point.

Starting with one woofer in a 2 way crossover and then adding the 0.5 way woofer makes more sense, although there is still a possibility to mess things at the crossover if the 0.5way woofer has still some output - in the end, the overall response must be considered.

I was believing , due to common designs have both woofers sharing the first LP stage, they were parallel (also if actually only in the overlapping freq. range), that's why...

Ok so I have to design something bigger than my hands can do...

thanks

[Jay_WJ]

What kind of drivers are you working with?