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#1 |
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diyAudio Member
Join Date: Jun 2007
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Hi everybody!
I mean the following problem: http://www.audiograph.se/subpages/te...damplifier.htm Can anybody explain this please? Is it common that an amp "sees" an impedance 4 times less than the nominal impedance of the loudspeaker? Or can it be 2 times less or 2 times more and so on? What are the deciding factors? Is it a part of a larger and overlooked "amplifier-loudspeaker inteface" problem? best, graaf |
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#2 |
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diyAudio Member
Join Date: Jul 2004
Location: Scottish Borders
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Hi,
my reading has revealed that it is possible for the speaker to demand much larger peak currents than a simple Vpk/Re or Vk/Rload would predict. I have accepted the argument that states that peak transient current approaches three times the current that using nominal impedance would predict and design the output stages to meet that demand. But, I have no proof of how accurate these guessimates/findings are.
__________________
regards Andrew T. |
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#3 |
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diyAudio Member
Join Date: Dec 2004
Location: Next door
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Hi,
Douglas Self addressed this problem in this article : "Loudpseakers undercurrents" Electronics World, February 1998, p98-99. More current demand than the voice coil DC resistance would demand can happen with asymetrical signals. Self thinks that a previous paper by Ottala in 1983 overestimated the problem. |
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#4 |
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diyAudio Member
Join Date: Nov 2003
Location: Brighton UK
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Hi,
I notice they use a speaker with a spectacularly bad impedance curve. The square wave impedance curve is a joke and is simply not impedance. Once you start fudging about you can show almost anything you like. I would not argue with AT's guesstimate for the current limiting of a nominal imnpedance load for a load tolerant amplifier. |
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#5 | ||
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diyAudio Member
Join Date: Jun 2007
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Quote:
this is an actual measurement of an actual loudspeaker the upper red corresponds to a conventional measurement the loudspeaker impedance with sine wave signal the lower blue graph corresponds to a measurement using a square wave signal Quote:
graaf |
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#6 | ||
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diyAudio Member
Join Date: Jun 2007
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Quote:
Quote:
what is impedance? is there "using of a sine wave signal" in the definition of impedance? I am just asking best, graaf |
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#7 |
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diyAudio Member
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You can plot the impedance of your own speaker easily with a meter that covers the required frequency range. Doug Self's method works well, connect a 600 ohm resistor in series with the speaker and drive this from 6 volts RMS. You can read in millivolts across the speaker the equivalent impedance at an frequency. So 4 millivolts is 4 ohms etc. Think I have remembered the values correctly.
And yes it is crazy- My B&W 703 an 8 ohm speaker has a 3 ohm minima ! |
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#8 | |
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diyAudio Member
Join Date: Jun 2007
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Quote:
best, graaf |
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#9 |
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diyAudio Member
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Good question, and I don't really know the answer to that one. I suspect not, certainly in the way you mean. Hard to explain this, the effect of the 600 ohms means the speaker is undamped, it's not like feeding it from a low impedance source. Dunno is the answer, try it
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#10 |
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diyAudio Member
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I will add to that, squarewave testing while incredibly useful in amplifier measurements etc, bears no relation whatsoever to anything you will see off a disc. The C.D. format cannot even reproduce a 1Khz squarewave that would be considered even "acceptable" in anything else. The 44.1 Khz sample rate ensures that. Music certainly contains nothing like this anyway.
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