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Old 21st January 2008, 12:16 AM   #1
mace is offline mace  United States
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Default resistor in series or parallel

Hello all,

I am starting a new project soon, and am just getting together my cx parts.
My problem is finding a 16 Ohm resistor with enough power handling to work in my woofer circuit. I am a noob at most of this, but from what I have read recently, I figure that if I wire 2 8 Ohm 12 watt resistors in series, this will give me a resistance of 16 Ohms and a power handling of 24 watt.

Am I correct???
Any help would be greatly appreciated. Thanks
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Old 21st January 2008, 05:52 AM   #2
Svante is offline Svante  Sweden
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Yes, you are correct.
Simulate loudspeakers: Basta!
Simulate the baffle step: The Edge
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Old 21st January 2008, 06:57 AM   #3
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In as far as you have told us, you are correct, but I think the deeper question is where and why are you putting a 16 ohm resistor in your woofer circuit?

I'm not saying you can't or shouldn't do that, but a few more details would help us understand.

Still, perhaps we don't need to understand, but you say you are a beginner and people here can offer a great deal of help and advice.

At the core of it all, two 8 ohm 12w in series indeed does equal one 16 ohm 24 watt resistor.

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Old 21st January 2008, 08:47 PM   #4
mace is offline mace  United States
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My reasoning on using the 2 8 Ohm resistors is to reach the 16 ohm requirement and increase power handling. I have read that a resistor in a woofer circuit requires a power handling of 15-20 watts. Is this not correct?
As I said before I am new at this, and it's definitely a learning experience. Below is a pic of the crossover.
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Old 21st January 2008, 09:21 PM   #5
Thawach is offline Thawach  Thailand
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you're correct.

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