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#1 |
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diyAudio Member
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Hello everyone, drawing a blank here.....
I am looking at the WR125ST, which is 85.6 dB w/ 1 watt. Since it is a 16-ohm nominal speaker, that is 4 Volts input. How do I determine the dB with 2.83 Volts (0.5 Watts) input? I know there is an equation out there, just can't seem to find it.
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#2 |
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diyAudio Member
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Just did a little experiment in Unibox. With 0.5 Watt, the output is at 82 dB, ~3 dB less. What is the equation the relates cutting the wattage in half, reduces dB by 3?
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#3 |
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diyAudio Member
Join Date: Nov 2003
Location: Brighton UK
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Hi,
Sensitivity should be stated as dB/2.83V independent of impedance. The standard version is 85.6 dB (? 86dB) 8ohm, expect 83dB for 16ohm. |
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#4 | |
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Speakerholic
diyAudio Moderator
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Quote:
The equation is 10X the power = 10 more dB. 2X power and 3 dB is close enough for approximating. |
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#5 | |
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diyAudio Member
Join Date: Feb 2004
Location: Stockholm
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Quote:
So if P/Pref=0.5, 10*log10(0.5)=10*0.301=3.01 dB. |
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