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#1 |
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diyAudio Member
Join Date: Nov 2007
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Hi everyone,
I want to use headphones with my guitar amp (head not combo), but there's no headphone socket. From research I've done so far, I understand I probably can't plug the headphones directly into the speaker output. Can anyone please advise on what I need to do? |
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#2 |
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diyAudio Member
Join Date: Jan 2002
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Resistive divider to drop the level down.
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#3 |
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diyAudio Member
Join Date: Mar 2003
Location: Exeter
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First question - what type of amplifier is it?
If it is has a valve output stage, then you will need to dummy load the output, which is fairly inconvenient. If it is a transistor amp, then no problem - a suitable resistive divider might consist of a 100 ohm resistor in series, wired from the output to the commoned tip and ring of the headphone jack socket, with a 10 ohm resistor in parallel (from common tip and ring to the sleeve). The sleeve connects back to the amp. 2 watt rated resistors ought to be fine - unless you want to play REALLY loudly....!
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John Audio |
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#4 |
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diyAudio Member
Join Date: Nov 2007
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Thanks both for your replies.
The amp in question is an Ashdown MAG300H. Its technical spec is here: http://www.ashdownmusic.com/bass/detail.asp?ID=112. I believe it is all-transistor. The minimum output loading is 4 ohms. John, I'm afraid I'm being somewhat dim but I'm finding it hard to form a clear mental picture of the scheme you're suggesting & I don't want to run the risk of messing-up. Would it be possible to post a simple sketch, please? Cheers, Mike |
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#5 |
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diyAudio Member
Join Date: Mar 2003
Location: Exeter
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Can't send you a PM - so you will have to e-mail me via my Web site:
www.orchid-electronics.co.uk JG
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John Audio |
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#6 | |
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diyAudio Member
Join Date: Jan 2002
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Quote:
From John's suggestions, R1=100, R2=10, Rsource=0, Rload=headphones, Vin is amp output, +=positive, -=negative |
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#7 |
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diyAudio Member
Join Date: Nov 2007
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Thanks, I'll give it a try.
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