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#1 |
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diyAudio Member
Join Date: Oct 2011
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I have access to some 300,000uF can-style capacitors. I was wondering if I could use them instead of 680uFs for input power caps. I know that the purpose of the caps are to reduce ripple, and wouldn't a stupidly large cap eliminate the ripple?
Why would I do this? Because I can. |
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#2 |
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diyAudio Member
Join Date: Feb 2003
Location: ..
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it can be bad for your transformer, diodes, fuse
big caps draw all of the required current from the xfmr sec in increasingly narrow, higher current pulses as the C goes up you can add some series R, make a "pi" filter with more reasonable caps next to the bridge Last edited by jcx; 16th October 2011 at 10:13 PM. |
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#3 |
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diyAudio Moderator
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Well those would indeed be stupid, but in a fun way.
![]() As JCX says, use a pi filter. Put a more sane cap value after the rectifier, then a resistor, then your stupid caps. That resistor will slow down the big current inrush. But you'll have the stupid big caps as the reservoir. The ripple won't get thru the resistor. Sounds like fun.
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#4 |
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is choosing a less facetious title...
diyAudio Member
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hahahahaha...... thanks you made my day!! good form I say. its all been said above, but i just had to register my approval of the scale of your supremely stupid capacitance =)
when you finish we demand pics!! |
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#5 |
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diyAudio Moderator
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Add a solar panel and charge the caps.
Design a micro power headphone amp and let the caps power it
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------------------------------------------------------- A simulation free zone. Design it, build it, test it. |
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#6 | |
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diyAudio Member
Join Date: Oct 2011
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Quote:
So... ![]() ? |
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#7 |
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diyAudio Member
Join Date: Jun 2011
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Just a thought, what if the enormous caps discharge unevenly upon power down?
That can put quite a bit on DC on the headphones for a good amount of time if there is no relay protection or coupling cap on the output |
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#8 |
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diyAudio Member
Join Date: Jul 2008
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Um. How would they discharge unevenly, given that they're connected at the ground? They'll try to keep at the same potential, even with different ESRs. Am I mistaken here?
But - two things: 1) 680uF might be too small for the first C. Try something around an order of magnitude better. 2)2k resistor is a LOT. That'll waste I^2 * R watts of power. And with 330k of capacitance you don't need a lot to eliminate ripple. You'll need to lower that quite a bit and you'll still need to get resistors with high wattage. It sounds like a lot of fun tho. I want to see pics of those beasts. |
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#9 | |
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diyAudio Member
Join Date: Oct 2011
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Quote:
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#10 |
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diyAudio Member
Join Date: Jul 2008
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6800 is fine. You can drive a headphone amp with that alone
![]() The resistor you can size based on how much power you can afford to lose. That depends on how much current will pass trough it. Let's say, for the sake of it, that your two channels will draw about 250mA each. That means you'd be drawing 500mA trough the resistor, which for 20 ohm will have to dissipate 10W. I'd be using 20W rated, heatsinked resistors for this, maybe more. Sounds a bit too wasteful, but on the other hand - you are putting 330k caps in this, so I'm guessing that nothing can be considered overboard
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