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#661 |
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diyAudio Member
Join Date: Jul 2004
Location: Scottish Borders
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Hi,
are you correctly terminating the unused input?
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regards Andrew T. |
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#662 | |
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diyAudio Member
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Quote:
Will be used with balanced preamp. |
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#663 |
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diyAudio Member
Join Date: Jul 2004
Location: Scottish Borders
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Hi,
if you feed an unbalanced signal into one pin of a balanced input, then the other pin must be terminated to allow the amp to correctly set the gain and input conditions. When you feed both pins with a balanced signal then the source resistances (Rs+Rs) terminate both pins for you.
__________________
regards Andrew T. |
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#664 |
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diyAudio Member
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Thanks Andrew.
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#665 |
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diyAudio Member
Join Date: Nov 2003
Location: Norway
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Now I got 2 pcs of filter boards, and one PSU, and I am now looking into ordering the right remaining parts....
I've been looking into this with the help of the "active_filter_four.xls"-file, but I have noticed that the values I get here is not the same as when calculated with the Linkwitz calculator from Sound Weshost (esp-lr12.exe). seems like the latter is build with C and 2C (or R and 2R...)in some sort of cascaded Butterworth configuration, while this approach uses the same values in all capacitors..(resistors)..!? Can someone please elaborate on this ? PS: Thanks to novec for sharing (selling..) his "spare" parts with me !... Lyra |
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#666 |
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diyAudio Member
Join Date: Sep 2003
Location: Upstate NY
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This board's filter topology is a little different than the one that the ESP calculator uses. These filters (and the spreadsheet) are set up as equal component value filters while ESP uses unity gain topology.
Notice the connections at the output of each opamp. These boards use a pair of resistors at the output to set the stage's gain (and Q) while the ESP filter connects the output of the opamp directly to the negative input. Q is set by the component values. You can use the ESP calculated values by jumpering the appropriate resistor in the gain setting pair and omitting the other. The advantage of equal component values is that you can buy more of a single value cap and match more easily, as well as possibly save some money. |
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#667 | |
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diyAudio Member
Join Date: Nov 2003
Location: Norway
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Quote:
Thanks....this was somewhat educating -and by this...the sound will be equally good no matter what topology I choose !??? -what would the best Q value of this filter be ??? (straight 24 dB rolloff both ways at aprox 80 Hz) -what Q value would correspond to the Unity Gain topology like ESP ? Lyra |
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#668 |
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diyAudio Member
Join Date: Sep 2003
Location: Upstate NY
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For a straight electrical Linkwitz Reilly you want a total Q of .5. If a 12 dB/octave filter set the filter Q to .5, if a 24 dB filter set each section to .7 because the total Q is the product of the filter sections' individual Qs.
Your actual Q should be whatever it takes to meet our target response with the drivers chosen. |
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#669 |
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diyAudio Member
Join Date: Nov 2003
Location: Norway
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In the manual it is stated:
<...Practically, You can use any value between 10 and 47 nF...> -Does this mean that I should avoid using 68nF or even 100nF ? (the latter is somewhat big compared to the footprint on the board, but it might go !?, but 68nF is just as big as the 47nF (MKP1837)) I kind of like the idea of using aprox 20-22k resistors rather than the somewhat larger values a 47nF cap requires...and...I got some 68nf/ 100nF laying around.... Lyra |
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#670 |
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diyAudio Member
Join Date: Sep 2003
Location: Upstate NY
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That should work fine if they fit. The tight tolerance caps I have are fairly big, which lead to the "practical" recommendation. Some loose tolerance caps are smaller, but be careful to select them for accurate values. I have used >100 nf caps where appropriate.
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