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12th March 2013, 10:53 PM  #11 
Speakerholic
diyAudio Moderator

Because the area of a trapezoid is
h(a+b)/2 where: h=height a=shorter of the parallel dimensions b=longer of the parallels 
12th March 2013, 10:56 PM  #12 
diyAudio Member
Join Date: Apr 2006
Location: MA

Math

12th March 2013, 10:58 PM  #13 
Speakerholic
diyAudio Moderator

Sorry, I'm supposed to have forgotten all this by my age.

12th March 2013, 11:08 PM  #14 
diyAudio Member
Join Date: Mar 2010
Location: Sweden

Shouldn't integrals work for this? Or am I wrong?
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12th March 2013, 11:12 PM  #15 
diyAudio Member
Join Date: Aug 2002
Location: victoria BC

for those with simple constant CSA just draw them out in CAD, and use the measure area function, snapping to intersection points, then times height
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12th March 2013, 11:13 PM  #16 
Speakerholic
diyAudio Moderator

Ghosts of departed quantities.

12th March 2013, 11:17 PM  #17 
frugalphile(tm)
diyAudio Moderator

Cal & X fighting over the use of the Associative property.
dave
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12th March 2013, 11:23 PM  #18 
Speakerholic
diyAudio Moderator

Associative property, really?
Is that what you get from the dimensions in post 1? 
12th March 2013, 11:25 PM  #19 
diyAudio Member

Has everyone actually forgotten there basic geometry? Cal, glad someones brain still works here and you go that right. Why would you have to use a cad program to figure this out? That is like asking what the area of a circle is! Now if we start talking about the sq. rt of 1 I imagine that many would not know the term i, but a simple trapezoid you could look that up on Google in two seconds. How do you do ac circuit work if you don't remember some basic math?

12th March 2013, 11:41 PM  #20 
diyAudio Member

I think we are on same thinking. Without a picture I interpreted trapezoid in the vertical dim with top wall and bottom wall being rectangular csa. I think you see this as a trapezoid csa on top and bottom wall of varying area  trapezoid in all dimensions. Not clear what op meant based on words. That's why we have diagrams. We are both right. Depends on interpretation. Heck op did not even give height. My formula of average areas on top and bottom multiplied by height applies to any cross section, round, trap, triangle, etc. As long as same type of cross section top and bottom.
Last edited by xrk971; 12th March 2013 at 11:44 PM. 
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