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Old 20th June 2007, 03:23 PM   #1
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Default Line Array Impedance HELP

I have 12 drivers at 6 ohms a piece that I am trying to configure into a line array, but I am struggling with the series/parallel wiring. My goal is to create a single load between 4-8 ohms.

Help please! If I need to add a few speakers to make it work-I can!

Thanks,
Dominick
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Old 20th June 2007, 04:08 PM   #2
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Wire 4 speakers in series to get 24 ohms. Do 3 sets of these and then parallel the three sets. This will get 8 ohms total. Maybe someone can diagram it for you.
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Old 20th June 2007, 06:46 PM   #3
adason is offline adason  United States
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no problem, go to zalytron (http://www.zalytron.com/) and scroll down to line arrays, see all the wireing diagrams
do power tapering, that sounds better
e
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Old 21st June 2007, 12:21 AM   #4
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happy, could you please explain step by step the math you used to get 8 ohms?

Because I am arriving at a figure much lower than that.

Thanks,
Dominick
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Old 21st June 2007, 12:47 AM   #5
saramac is offline saramac  United States
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Go to 12volt.com There are Impedence calculators there that will help you
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Old 21st June 2007, 12:52 AM   #6
saramac is offline saramac  United States
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I'm sorry it's The12volt.com It loads slow but has what you need. Dig around that site for an impedence calculator.
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Old 21st June 2007, 01:14 AM   #7
bluegti is offline bluegti  United States
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First wire 3 sets of 4 drivers in series.

Rseries = R1 + R2 + R3 + R4
or
Rseries = 6 + 6 + 6 + 6
or
Rseries = 24

Next wire the 3 sets of drivers in parallel.
(1/Rtotal) = (1/R1) + (1/R2) + (1/R3)
or
(1/Rtotal) = (1/24) + (1/24) + (1/24)
or
(1/Rtotal) = (0.0416667) + (0.0416667) + (0.0416667)
or
(1/Rtotal) = 0.125 (I removed the rounding error)
or
Rtotal = 1/0.125
or
Rtotal = 8

Hey... I actually learned something useful in Physics class.
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Old 21st June 2007, 11:48 AM   #8
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Thanks a ton--I have it working now-what I did wrong was place a single copper stand accross the terminals insteat of terminating them in between! What an amateur move.

Thanks guys!

Dominick
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