Power factor calculation
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 11th March 2007, 03:35 PM #1 Netlist   diyAudio Moderator Emeritus     Join Date: Jan 2003 Power factor calculation How to calculate the ratio of resistive and reactive load if the impedance/resistance is not measurable? http://www.ibiblio.org/kuphaldt/elec...html#02216.png As a practical example, I’d like to measure the cos(phi) of an energy saving light bulb which states to consume 8W but measures 230V * 0.057A = 13.1W. Of course, believing the manufacturer is the easiest, 13.1W – 8W gives a power factor of 0.61 but I'd like to verify. Out of circuit, the bulb has an infinite resistance probably caused by the internal ignition circuit. /Hugo
 11th March 2007, 03:59 PM #2 sreten   diyAudio Member RIP   Join Date: Nov 2003 Location: Brighton UK Hi, Said bulbs have a complex supply / ignition circuit. You cannot derive the power factor from that simple formula. Only way I know of is a small additional resistor and an oscilloscope. /sreten.
 11th March 2007, 04:30 PM #3 Netlist   diyAudio Moderator Emeritus     Join Date: Jan 2003 Say a 10ohm resistor in series and go from there? /Hugo
 11th March 2007, 05:11 PM #4 sreten   diyAudio Member RIP   Join Date: Nov 2003 Location: Brighton UK Hi, Yes. With an oscilloscope you can then see the current and its relationship with input voltage. May not be continuous. /sreten.
 11th March 2007, 05:21 PM #5 Netlist   diyAudio Moderator Emeritus     Join Date: Jan 2003 Thanks. Would there be a way to compensate these bulbs for a higher power factor. I calculated a 457µF (!) capacitor would bring the power factor close to 1. Apart from the fact that its rather silly to do, I'm trying to get a grasp of the basic math. /Hugo

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