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Old 17th December 2005, 07:32 AM   #1
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Default Power Amplifier -> Computer Sound Card

Seems there aren't many posts about this. I want to do some experimenting with Rightmark, and I'd like to keep it simple, but avoid smoking an expensive soundcard.

How's this?
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Old 20th December 2005, 10:09 AM   #2
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One bump...just because I thought someone might have done this, or something close.
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Old 20th December 2005, 12:06 PM   #3
johnnyx is offline johnnyx  United Kingdom
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The Liberty Audiosuite probes had a series resistor of 47k Ohms in the hot lead, mounted at the probe end of the cable. This went straight into the soundcard, and was good for up to 30v. For higher voltages, the resistor would be increased. This was for the Turtle Beach Fiji soundcard, though I suspect it would suit others. The series resistor would limit input current, and forms a potential divider with the soundcard's input impedence. I would start with a 47k series resistor and see how it goes. It might be a good idea to monitor the soundcard's input voltage at first to see how much the input is attenuated by the series resistor.
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Old 20th December 2005, 12:32 PM   #4
SY is offline SY  United States
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I built a little buffer using a BUF03. The input is shunted by a 1M resistor and a 20pF cap. That way, I can use a 10:1 scope probe to attenuate high level signals. If there is offset (e.g., measuring the signal on a tube plate), I capacitively couple to the probe.

The whole shmeer can be built with a couple of 9V batteries into an Altoids box.
"You tell me whar a man gits his corn pone, en I'll tell you what his 'pinions is."
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Old 20th December 2005, 11:08 PM   #5
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I'm afraid that 10:1 isn't enough... I have a E-MU 0404 sound card on the way, and I understand that it is rated for a 'nominal' input of -10dbV (300mV), and a max input of 6dbV (about 2V). So a 10:1 would only allow a max input equivalent to the full output of a 50W amp.

I thought a 10:1 divider in conjunction with the pot would allow me to get the flexibility I'd need. Is my reasoning flawed? (more than usual, that is... )
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