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Old 2nd November 2005, 11:01 AM   #1
Duo is offline Duo  Canada
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Default I've done it now....

Well, here it is, the lamest project of the end of the year 2005.

I found that a cheap soldering iron of mine simply got too hot to be really useful. I was always tinning it to keep from oxidation and the heat output was just too much.

My solution to the problem? PWM, yes, Pulse Width Modulation.

But the way I implemented it is what's so demented..

The idea came about easily and soon I began constructing the circuit from the top of my head. I started with an astable multivibrator using two transistors, then an RC integrator, then a single transistor comparator, then relay driver. Boy what a novel PWM device. It happens to operate at about 4Hz and with a pot varying the voltage to the emitter of the comparator, I can vary the duty cycle anywhere from 0% to 100%.

The verdict? As ugly as this is, it performs beautifully. The temperature of the iron is now easy to control at the turn of a knob and there's no longer any high heat output mess happening.

Just thought I'd add this archaicly styled circuit to the ideas of diy'ers...
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Old 2nd November 2005, 11:03 AM   #2
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Do you have any temperature sensing, or do you just try out what setting works?
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Old 2nd November 2005, 11:12 AM   #3
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There is no sensing. I didn't need it to have feedback.

I just base it on duty cycle. 50% duty is half the power, therefore half the heat.

It works well. I now can solder properly and not worry about the tip burning away.
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Old 2nd November 2005, 11:22 AM   #4
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50% duty is 1/4 the power
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Old 2nd November 2005, 11:24 AM   #5
Duo is offline Duo  Canada
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Yes, you are correct.

It's 4:00am, can you lay a blame on me?
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Old 2nd November 2005, 11:25 AM   #6
dnsey is offline dnsey  United Kingdom
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Mine's even more archaic - uses a simmerstat (cooker control) to do much the same thing
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Old 2nd November 2005, 11:25 AM   #7
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Quote:
Originally posted by richie00boy
50% duty is 1/4 the power
No, only if you low-pass filter the voltage, which is hardly the case in this application. In this case, 50 % duty cycle would probably mean that there is 100 % power 50 % of the time.
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Old 2nd November 2005, 11:29 AM   #8
Duo is offline Duo  Canada
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You guys have me spinning now. I'm too tired to really think.

You are correct Christer in that it is 100% power half of the time.

Then again, in typical PWM systems, I believe richie00boy is correct.


EDIT: But let us not argue over the numbers too much. I just wanted to show my solution to the problem that faced me.
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Old 2nd November 2005, 11:59 AM   #9
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The thermal inertia of the iron will perform the integrating action akin to low-pass filtering so the net result will be the tip effectively sees 1/4 power

But yes electrically it's 100% power 50% time.
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Old 2nd November 2005, 12:05 PM   #10
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Yes, the thermal inertia will work as a low-pass filter for the temperature. That means the temperature will be fairly stable and the same as if we had had 50 % power 100 % of the time. What temperature we actually get is a different issue, though. The relationship between power and temperature is all but linear.
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