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Old 28th March 2005, 05:31 PM   #1
pburke is offline pburke  Germany
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Default How to reduce attenuation of a 25k pot?

Hi,

I have a couple nice 25K Noble pots and would like to use them for a headphone amp/DAC output (DDDAC1543 with 16 DAC chips). The problem is that the attenuation of those pots is far too aggressive for what I need. No matter how I wire them, it's almost an on/off situation. I think a 2k attenuator would be more appropriate for what I need.

Can I just add a resistor in parallel with the attenuator to reduce it's range, or would that mess up the pots logarhythmic curve?

Peter
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Old 28th March 2005, 06:01 PM   #2
homer09 is offline homer09  Canada
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i dont see how a different value pot will attenuate less or more.

sounds to me like you wired your pot wrong. A properly wired pot functions as a voltage divider. What determines attenuation is ratio between the two parts of the resistor (separated by the wiper). So if you have a 2k pot or a 1Meg pot, the attenuation will be the same!

check that you have not wired your pot backwards as an anti-log pot. This would mean that instead of voltage input slowly increasing in a logarithmic fashion, it would go the other way, increase very fast than slowly producing an almost on/off behaviour when used as a volume control.
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Old 28th March 2005, 06:10 PM   #3
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It sounds to me like you have the phones attached to the pot wiper. If that's the case you are going to need a headphone amplifer circuit after the pot.
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Old 28th March 2005, 06:32 PM   #4
pburke is offline pburke  Germany
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actually, the pot was wired correctly and the wiper was going to ground. However, I had it before the coupling caps and not after, which messed with the DAC's vref... d'uh!

trying it behind the caps now.

Peter
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