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#1 |
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diyAudio Member
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Does anyone know the frequency response of air and formulas that describe it ?
I was thinking about how much attenuation at different frequencies and different distances from a sound source mike |
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#2 |
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diyAudio Member
Join Date: Nov 2003
Location: Brighton UK
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Farfield nearly all sound sources will follow the inverse square law,
this dominates any attenuation or frequency dependent losses. sreten.
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#3 |
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diyAudio Member
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OK sure, but I wondered within this, wether some frequecies that are attenuated more that others due to the charactoristics of the air.
By way of example, I get the feeling that square wave leading and perhaps trailing edges will be softened with distance. mike |
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#4 |
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diyAudio Member
Join Date: Nov 2003
Location: Brighton UK
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Its the different speed of sound through air at different densities
that effectively kills high frequencies through phase interference and frequency spreading. A sharp lightening transient will be spread by the different speeds of sound in the various atmospheric layers, as it spreads its frequency components wil continually lower, giving only the rumble effect at long distances. sreten.
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#5 |
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diyAudio Member
Join Date: Sep 2002
Location: Sweden
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I also think the humidity of the air matters, or at least I get the
impression that higher frequencies are more attenauted when it is very humid. |
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#6 |
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diyAudio Member
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I think he wants to know about ultrasonics. Like, are they attenuated any more than otherwise?
Speaking of which, something I've always wondered is just how high a frequency can be transmitted acoustically - I know over 100kHz exists! Tim
__________________
See my Electronics webpage -- the home of Vacuum Tube Drag Racing. The key to being a successful Audiophile: "I reject your reality and substitute my own!" |
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#7 | |
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diyAudio Member
Join Date: Sep 2002
Location: Sweden
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Quote:
John Iversons ultrasonic speakers? |
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#8 | |
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diyAudio Member
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Quote:
Ideally I would like to see frequency response graphs 10hz - 100khz at 1 meter, 2m, 3m, 4m, 5m. what happens to a square wave leading edge would also be interesting. |
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#9 | |
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diyAudio Member
Join Date: Jun 2001
Location: Eugene, OR
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Quote:
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