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#11 |
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diyAudio Member
Join Date: Jul 2001
Location: The Netherlands
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Ha
it seems that DIN IEC 651 = C weighting back to google... |
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#12 |
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diyAudio Member
Join Date: Oct 2003
Location: The Netherlands
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The difference in dB between the results of different noise measuring filters depend on the character of the noise. For instance, if your noise is completely white, then there is a difference between A-weighting and flat (20Hz-20kHz bandlimited) of approximately 3dB (dBA is 3 dB better than flat). CCIR gives far worse results.
If your noise is not white, the difference might become much more, e.g. if you have 50Hz/60Hz hum in your noise the flat value will change a lot, but the A weighted value far less because the A-weighting takes these low frequencies not so much into account. A-weighting is also less critical about the noise above 5kHz. If you have a circuit that uses FETs or MOSFETs you may have quite an amount of 1/f noise, typical corner frequencies between 100Hz (good FETs) and even 10kHz (MOSFETs). In these cases the difference between A-weighting and 20Hz-20kHz flat will be more than 3dB. These kind of differences you also get with digital audio circuits. Multibit ADCs and DACs generate mostly white noise (quantisation noise), but bitstream (sigma-delta) type of converters generate more high frequency noise because of the applied noise shaping. Bitstream converters are almost allways measured with A-weighting of the results, then you get (much) better values. Steven |
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#13 |
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diyAudio Member
Join Date: Jul 2001
Location: The Netherlands
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Thanks Steven..
any idea what a CCIR weigthing curve actually is and why? Regards, Thijs |
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#14 |
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diyAudio Member
Join Date: Nov 2002
Location: Netherlands
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Hi Thijs,
Here is a site that gives you the pole and zero locations of the various weighting filters: http://www.ptpart.co.uk/noise.htm If you are familiar with the basics of filter theory you can build them. BTW searching around the net I found several times that the difference between flat and A-weighting filters for white noise is 10 dB when integrated over the 20 – 20 kHz bandwidth. Is there a mathematician out there to check this? Also this is informative reading: http://www.dwelle.de/rtc/infotheque/...ualpar_05.html Cheers |
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#15 |
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diyAudio Member
Join Date: May 2001
Location: London UK
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These kind of differences you also get with digital audio circuits. Multibit ADCs and DACs generate mostly white noise (quantisation noise), but bitstream (sigma-delta) type of converters generate more high frequency noise because of the applied noise shaping. Bitstream converters are almost allways measured with A-weighting of the results, then you get (much) better values.
-------------------------------------------------- The specs can cheat; although this is supposedly based on human response to sine waves! I always look at broadband noise first. The A weighting can hide a lot of circuit probelms. |
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#16 |
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diyAudio Member
Join Date: Oct 2003
Location: The Netherlands
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Hi Thijs,
Have a look at http://www.rane.com/par-w.html where you can find the subjects A-weighting and C-weighting. It appears that CCIR (now ITU-R) has its source in telephony switching. Hi Pjotr, Also here a difference of 10dB between flat and A-weighted figures is mentioned by Dennis Bohn, but more as a warning that the difference can be as big as 10dB in case of 'nasty low-frequency hum components'. Normally for white noise it is my experience (no mathematics) that the difference is some 3dB. In the past, I found this numerous times when measuring noise with a Sennheiser UPM550 and switching between flat 20Hz-20kHz and A-weighted. Steven |
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#17 |
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diyAudio Member
Join Date: Nov 2002
Location: Netherlands
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Hi Steven,
Maybe you are right that the 3 dB figure is more close. Most of the att. is at the lower frequencies for an A-weighting filter and most of the energy of white noise is in the upper frequencies above 1 kHz where the filter att. is much lesser. Also the method of measuring makes sense, is it quasi peak or is it true RMS? For true RMS you can calculate mathematically the difference by integrating the noise content along the filter slope. But I am too lazy to blow the dust from my old schoolbooks Cheers |
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#18 |
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diyAudio Member
Join Date: Jul 2001
Location: The Netherlands
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Thanks guys,
excelent reading! Regards, Thijs |
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#19 |
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diyAudio Member
Join Date: Mar 2003
Location: Haarlem, the Netherlands
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I once numerically calculated the noise bandwidth of an A filter. Theoretically, with white noise at the input, the RMS noise at the output of an A filter with unity gain at 1kHz should be identical to the noise at the output of a brick-wall filter with unity pass band gain and a 13471Hz bandwidth. That's 1.712dB less than in a 19980Hz bandwidth.
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