Transfer Funtion of the given circuit ? - diyAudio
 Transfer Funtion of the given circuit ?
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diyAudio Member

Join Date: Nov 2009
Location: Ghaziabad (Delhi NCR)
Transfer Funtion of the given circuit ?

Hi,

Please give me the transfer function of the following circuit. Where R1,R2,R3,R4 and R5 are not equal.
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Regards,
Sameer Dhiman

 8th October 2011, 12:00 PM #2 diyAudio Member   Join Date: May 2007 How many marks will your teacher give me for the answer?
diyAudio Member

Join Date: Jun 2002
Location: USA, MN
Quote:
 Originally Posted by sameerdhiman Hi, Please give me the transfer function of the following circuit. Where R1,R2,R3,R4 and R5 are not equal.
You should check out a neat little program called sapwin
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 8th October 2011, 04:20 PM #4 On Hiatus     Join Date: Oct 2002 Location: Chicagoland Blog Entries: 2 Just remember that the voltages at inverting and noninverting inputs are equal, that the current flowing into the inverting and noninverting inputs is zero, and it will be pretty easy to set up the basic equations to solve for Vo/Vi. __________________ "You tell me whar a man gits his corn pone, en I'll tell you what his 'pinions is."
 8th October 2011, 08:57 PM #5 diyAudio Member   Join Date: Feb 2003 Location: .. it actually "safer" to explicitly include op amp gain "A" and derive the equations you can always take the limit as A goes to infinity later - but by assuming it from the start you may save a term or two in the calculations or you may have your solution "blow up" from the infinity you are implicitly carrying around the op amp Howland current source is a favorite nasty problem set for those not understanding the "null injection" implicit infinity
 8th October 2011, 09:24 PM #6 diyAudio Member     Join Date: Mar 2011 Location: St Louis, Mo What method do you think is best for solving this problem, and how far along did you get? Dale
 10th October 2011, 03:48 PM #7 diyAudio Member   Join Date: Nov 2009 Location: Ghaziabad (Delhi NCR) @DF96 I am not a student in any institute so do not expect any Marks. @SY, jcx Thank you, I solved it using superposition theory. R1 and R2 forms voltage divider for Non-Inv voltage. R3||RD forms Rg and R4 forms Rf. So Non-Inv, Inv output voltage will be Vninv = V1*[R2/(R1+R2)]*[1+{R4/(R3||RD)}] Vinv = V1*-(R4/R3) Vout = Vninv + Vinv __________________ Regards, Sameer Dhiman
 10th October 2011, 05:22 PM #8 diyAudio Member     Join Date: Oct 2006 Location: Charlotte, NC Would you not want Vout in terms of V1 ?
diyAudio Member

Join Date: May 2007
Quote:
 Originally Posted by sameerdhiman I am not a student in any institute so do not expect any Marks.
Good. Sorry for jumping to conclusions, but your question looked like homework.

I'm not certain that your result is correct. I would expect to see two simultaneous equations involving Vin and Vout, which you then invert to get Vout in terms of Vin. What is RD?

 10th October 2011, 07:17 PM #10 diyAudio Member   Join Date: Nov 2009 Location: Ghaziabad (Delhi NCR) Sorry, R5=RD (In practical circuit R5 will be variable resistor e.g. JFET or LDR) I've verified the equation with LTSpice. If you any other equation/solution please post that. __________________ Regards, Sameer Dhiman

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