Transfer Funtion of the given circuit ? - Page 2 - diyAudio
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Old 10th October 2011, 07:43 PM   #11
DF96 is offline DF96  England
diyAudio Member
Join Date: May 2007
OK, I see how you have done it. Split node 1 into two independent inputs, then add the result. What confused me was your nomenclature: I assumed that Vninv was the voltage at the noninverting input, when in fact it is the output due to the input at the noninverting input.
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Old 11th October 2011, 07:55 AM   #12
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Join Date: Nov 2009
Location: Ghaziabad (Delhi NCR)
Now you got it.

Vninv is non-inverting output voltage which is equal to

Vinput * Resistor-Divider Output * Non-Inverting Gain

Vinv is inverting output voltage which is equal to

Vinput * Inverting Gain

Final output voltage will be sum of Vninv and Vinv

Am I correct ?
Sameer Dhiman
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Old 11th October 2011, 12:02 PM   #13
DF96 is offline DF96  England
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Old 11th October 2011, 12:23 PM   #14
AndrewT is offline AndrewT  Scotland
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Join Date: Jul 2004
Location: Scottish Borders
I fell into the same tiger trap as DF96.
Vinv = input voltage at -IN pin.
Vninv = input voltage at +IN pin

Silly me for reading what it said,
Instead I should have reverse engineered the given equations and realised that Voutinv=Vinv and Voutninv=Vninv are the only way to make your equations work correctly !!!!
regards Andrew T.
Sent from my desktop computer using a keyboard
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