Transfer Funtion of the given circuit ?
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 10th October 2011, 08:43 PM #11 DF96   diyAudio Member   Join Date: May 2007 OK, I see how you have done it. Split node 1 into two independent inputs, then add the result. What confused me was your nomenclature: I assumed that Vninv was the voltage at the noninverting input, when in fact it is the output due to the input at the noninverting input.
 11th October 2011, 08:55 AM #12 sameerdhiman   diyAudio Member   Join Date: Nov 2009 Location: Ghaziabad (Delhi NCR) Now you got it. Vninv is non-inverting output voltage which is equal to Vinput * Resistor-Divider Output * Non-Inverting Gain Vinv is inverting output voltage which is equal to Vinput * Inverting Gain Final output voltage will be sum of Vninv and Vinv Am I correct ? __________________ Regards, Sameer Dhiman
 11th October 2011, 01:02 PM #13 DF96   diyAudio Member   Join Date: May 2007 Yes.
 11th October 2011, 01:23 PM #14 AndrewT   diyAudio Member   Join Date: Jul 2004 Location: Scottish Borders I fell into the same tiger trap as DF96. Vinv = input voltage at -IN pin. Vninv = input voltage at +IN pin Silly me for reading what it said, Instead I should have reverse engineered the given equations and realised that Voutinv=Vinv and Voutninv=Vninv are the only way to make your equations work correctly !!!! __________________ regards Andrew T.

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