|
|
|||||||
| Home | Forums | Rules | Articles | Store | Gallery | Blogs | Register | Donations | FAQ | Calendar | Search | Today's Posts | Mark Forums Read | Search |
| Everything Else Anything related to audio / video / electronics etc) BUT remember- we have many new forums where your thread may now fit! .... Parts, Equipment & Tools, Construction Tips, Software Tools...... |
|
Please consider donating to help us continue to serve you.
Ads on/off / Custom Title / More PMs / More album space / Advanced printing & mass image saving |
|
|
|
Thread Tools | Search this Thread |
|
|
#1 |
|
diyAudio Member
Join Date: Mar 2007
|
Hi guys. I'm taking some online lessons in circuits and have a question about interconnects and speaker cables. In my current lesson, it says that capacitors pass voltage when it changes and acts like a short with dc. So, if it will pass changing voltage, which music is, changes all the time, why is capacitance bad in a cable?? Seems like it wouldn't matter, as the message(music) would get through just fine?? On the other hand, I want to make some interconnects and all the sites i have been to mention capacitance as an evil that must be avoided. How come?? Don't flame me too badly guys, I'm only trying to learn something. Thanks and regards, J.D.
|
|
|
|
|
#2 |
|
diyAudio Member
|
Interconnects... two cables running together (the inner core and outer shield) form a capacitor. In effect they are two plates side by side. Longer lead length = larger value of capacitance. So far so good
The output of a source component is not zero ohms but some other (usually low but not always) value. So if the output impedance was highish then the capacitance of the lead would form a simple R/C filter and roll off or attenuate the high frequencies. In practice it's not such a problem with normal length interconnects. Speaker leads... same applies in theory... in practice the output impedance of an amplifier is always low so the attenuation thing isn't an issue. Also small levels of capacitance can cause instability if say an interconnect were connected directly to the output of a high speed opamp.
__________________
------------------------------------------------------- A simulation free zone. Design it, build it, test it. |
|
|
|
|
#3 |
|
Rebel Samurai!
diyAudio Member
|
The two conductors bound together act like the two plates of a capacitor, so that's where the capacitance comes from. But it's not capacitance from one end of the conductor to the other (which would pass AC, like you're talking about*), it's from one conductor to another. So at (very) high frequency the capacitive cable acts like a short. Well, that's the extreme case, more likely it just throws something else off.
* Your cables would make a very small capacitance, most likely, and wouldn't be useful for passing music even if it was in this alignment. My understanding, anyway. Last edited by AdamThorne; 29th July 2011 at 06:34 PM. |
|
|
|
|
#4 |
|
diyAudio Member
Join Date: May 2007
|
A coupling capacitor (passes AC, blocks DC) is in series with the signal; together with the input resistance of the next stage it forms a high-pass CR filter so the capacitance value must be high enough to pass the lowest frequencies. Have a look at CR filters.
Cable capacitance is in parallel with the signal, so together with the output resistance of the previous stage it forms a low-pass CR filter so the capacitance value must be low enough to avoid reducing the highest frequencies. You need to understand these basics before worrying about other effects which may or may not happen. Bear in mind that cables are a topic that people argue about. |
|
|
|
|
#5 |
|
diyAudio Member
Join Date: Mar 2007
|
Thanks guys. Knew this was the place to ask. Thank you for keeping it simple. I understood what you fellas were saying!!!!! Must be learning something. Much appreciated guys. Best regards, J.D.
|
|
|
|
|
#6 |
|
diyAudio Member
Join Date: Sep 2006
|
One more thing, and I hope it will not confuse the issue too much: capacitance in a cable is not the same as pure capacitance in a component f.e.: it is partially or completely balanced by the inductance of a cable.
This means that you can carry broadcast quality signals on hundreds of feets of cable. There are second order effects that limit the bandwidth, but anyway, capacitance is not the primary limiting factor: in a speaker cable, inductance is the dominant one, because the charateristic impedance of the cable (something like 80 ohm, for ordinary cable) is much higher than the impedance of your speakers. |
|
|
|
|
#7 |
|
diyAudio Member
Join Date: Mar 2007
|
Thank you all. Well spoken fellas in language i could understand!!! Never occurred to me that it was in parallel instead of series. Duh. Well, like i said, i'm learning. Thanks again fellas, really appreciate it. Best regards, J.D.
|
|
|
|
|
#8 | |
|
diyAudio Member
Join Date: May 2007
|
Quote:
(OP please ignore this post if it confuses you - Elvee and I are talking about more complicated effects than simple CR filters). |
|
|
|
|
|
#9 | |
|
diyAudio Member
Join Date: Sep 2002
Location: Lakewood, Ohio
|
Quote:
But more correctly it's also the leakage resistance of the insulator (conductance) that makes the formula very messy at audio frequencies. Once we get to radio frequencies we can use the simpler formula.
__________________
Kevin |
|
|
|
|
|
#10 |
|
diyAudio Member
Join Date: Jan 2010
Location: Jeffersonville, Indiana USA
|
Another way they describe the parallel capacitance of a cable (say an RCA jack cable) is "parasitic" capacitance, that is it takes current to drive it, that doesn't get to the end and do anything useful. Current costs money. Right now, LM4560 op amps that will drive a lot of current very fast, are over $2, whereas 4558's that won't put out much current fast at all, are about $.25. The power supply that will drive a 24 channel mixer board with LM4560's is a lot more expensive than the power supply that only has to support 24 channels of 4558 op amps. That 100' snake cable from mixer to power amp, has a whole lot of parasitic capacitance. Before "electret" mikes with a little internal amp, you couldn't put the mikes 100' from the mixer, because the mikes wouldn't drive the capacitance of the cable without a mike amp up there on stage. "Dynamic" mikes that would drive a lot of cable, didn't pass many high frequencies so they weren't much use for symphonies, only voice and pop bands. High frequencies from a medium source impedance like a dynamic mike, get lost in the capacitance of the cable.
Another example- a popular phono preamp from 1961 was the tube PAS2. It only put out enough current to drive the parasitic capacitance of a 6' RCA cable, plus the input of the power amp. There were other preamps that would drive a lot more cable, but they didn't sell as well because they cost a lot more, using more capable, lower volume tubes and a bigger power supply. As well, the preamp had to be less than 6' from the magnetic phono cartridge on the turntable, because the un-amped cartridge can't drive the parasitic capacitance of more RCA cable.
__________________
Dynakit ST70, ST120, PAS2,Hammond H182(2 ea),H112,A100,10-82TC,Peavey CS800S,SP2-XT's, T-300 HF Projs, Steinway console, Herald RA88a mixer, Wurlitzer 4500 Last edited by indianajo; 30th July 2011 at 12:50 AM. |
|
|
| Currently Active Users Viewing This Thread: 1 (0 members and 1 guests) | |
| Thread Tools | Search this Thread |
|
|
|
|
||||
| Thread | Thread Starter | Forum | Replies | Last Post |
| Trafo bad, or am I bad | caxxxxxx | Chip Amps | 24 | 3rd May 2011 08:56 AM |
| How much (capacitance) is too much? | dobias | Power Supplies | 56 | 10th April 2011 08:29 AM |
| Too much capacitance? | HaLo6 | Power Supplies | 24 | 14th June 2009 05:55 PM |
| from A(udiobahn) to Z(apco) amps, what makes it so good or bad? | profuse007 | Car Audio | 2 | 14th February 2006 01:46 PM |
| How much capacitance? | theAnonymous1 | Solid State | 4 | 22nd June 2004 08:01 AM |
| New To Site? | Need Help? |
| Page generated in 0.11602 seconds (82.10% PHP - 17.90% MySQL) with 10 queries |