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Old 20th February 2011, 10:28 AM   #1
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Post Bubba Oscillator Calculation

Dear All
I wanted to construct the Bubba Oscillator @ 1kHz. ButI ma not able to get the exact formula. I have lloked the net only all refers to TI pdfs. One of the documents (not of TI) said that the formula is 1/(2*pi*r*c*sqrt(6)) . Is this correct? what precautions to take while making one .

please help

rgds
jayant
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Old 12th October 2011, 12:01 PM   #2
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Old 12th October 2011, 12:33 PM   #3
DF96 is offline DF96  England
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No sqrt(6) in the formula, should be just f=1/(2 pi R C). This is because each CR gives 45 degrees phase shift.
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