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#1 |
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diyAudio Member
Join Date: Mar 2009
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I know I can take the difference of the left and right channels (L-R) to produce a quasi rear channel. The sum of L and R to get a center channel or mono sound. The problem is, if there is a signal in only L or R channel it still appears quite strong in the mono (L+R) channel. It is fine and quite normal, but lets say I want to diminish output to the center channel unless the signal is common to both channels, how can I do this? I'm guessing some sort of multiplier, So 2L*0R = 0C, or 2L*2R=4C
This is not a home theater project, but listening to only the L, R, L-R or L*R lets me here instruments or vocals that were covered by the louder vocals or instruments. |
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#2 |
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diyAudio Member
Join Date: Nov 2009
Location: Cape Town
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I'm pretty sure it's not possible to extract only the common signal.
btw - multiplication will give pure distortion e.g. piano * trumpet = nasty mess |
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#3 |
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diyAudio Member
Join Date: Mar 2007
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Take the FFT and look at what's common to both?
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"Fully on MOSFET = closed switch, Fully off MOSFET = open switch, Half on MOSFET = poor imitation of Tiffany Yep." - also applies to IGBTs! |
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#4 |
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diyAudio Member
Join Date: Feb 2004
Location: Northern California
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This has been something I have thought about doing for
years without getting to a good conceptual answer. The FFT analysis might work but I'm not sophisticated enough to judge that possibility. My basic notion is that you would have vastly improved image stability, potentially more accurate as well, with a true center only (common) signal. Two speakers, near left and right, with the standard stereo signals, and far left and right channels with the left and right only signals. I'd love to hear that. I have never heard nor seen a mathematical description of the trifield method of synthesizing multiple channels from a stereo signal. I have heard it done on Meridian systems and it's impressive. Jim Bongiorno sells a box that creates three channels, I believe on the same or similar principles. Let's hope this thread brings some approaches to light along those lines. Skip |
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#5 |
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diyAudio Member
Join Date: Jan 2006
Location: Johannesburg, South Africa
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It can only be done digitally. Done, I believe, by means of autocorrelation.
The later Dolby Pro-Logic decoders did this to extract the dialogue channel (I have a Yamaha DSP1000 that does this - that part of it is quite effective, but overall it is not a pleasant sounding piece of machinery) Once you have the common signal, you can subtract it by analogue means from the matrixed Left channel and matrixed Right channel signals to get a more-left-than-left and more-right-than-right.
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Steerpike's Toybox |
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#6 |
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diyAudio Member
Join Date: Jun 2002
Location: USA, MN
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L, R, L+R and L-R are all you can do passively, AFAIK
__________________
Our species needs, and deserves, a citizenry with minds wide awake and a basic understanding of how the world works. --Carl Sagan Science is a way of thinking much more than it is a body of knowledge. --Carl Sagan Last edited by Ron E; 13th February 2010 at 09:53 PM. |
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#7 |
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diyAudio Member
Join Date: Jan 2008
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What if you were to do:
"Common Channel" = L - (L-R) Doing L-R should leave you with the material which exists only in the left channel. Subtracting that from the left channel should give you only the material which is common to both channels. I can't see why it wouldn't work, but it seems too obvious to have been overlooked. What am I missing? |
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#8 |
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diyAudio Member
Join Date: Jan 2006
Location: Johannesburg, South Africa
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l - (l-r) = + r
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Steerpike's Toybox |
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#9 |
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diyAudio Member
Join Date: Jan 2008
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I can see that algebraically, but I'm having trouble with it logically. Shall have to break out Audacity and prove it to myself, I guess....
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#10 |
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diyAudio Member
Join Date: Feb 2010
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