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#1 |
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diyAudio Member
Join Date: Mar 2005
Location: Melbourne
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I recently took in a light presentation about acoustics and treatments in small rooms.
The presenter demonstrated a handy-looking spreadsheet that when calculating room nodes, there was a subsequent function which determines the density, or such, for any given nodes. Parameters I have so far: Lx (length) Ly (width) Lz (height) V (volume) A (surface area) Nx (modes of Lx) Ny (modes of Ly) Nz (modes of Lz) Fn,n,n (mode frequencies, i.e. F[0,0,1];F[2,1,3];etc.) up to N=4 Fc (diffraction mode?Schroder frequency) Rt60 (calculated from V, A and Fc) dc (Rt60 distance) and a dumb-looking graph can anyone help me with a method to calculate the sound density at a given node's corresponding frequency? thanks Simon (btw, this is intended as "research" for an interesting maths vs. reality for my in-car audio project)
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#2 |
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diyAudio Member
Join Date: Jun 2002
Location: USA, MN
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I've been down this road, and there is not much useful you can calculate from these parameters - it all depends on how far you go.
All small rooms are bad regardless of modal density. Rooms with duplicate dimensions are really bad. Damp out early reflections, that is all you need to know unless you are building a studio.
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Our species needs, and deserves, a citizenry with minds wide awake and a basic understanding of how the world works. --Carl Sagan Science is a way of thinking much more than it is a body of knowledge. --Carl Sagan |
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#3 |
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diyAudio Member
Join Date: Jun 2002
Location: USA, MN
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If you don't wish to heed my earnest advice and forget about it, go here: http://www.silcom.com/~aludwig/
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Our species needs, and deserves, a citizenry with minds wide awake and a basic understanding of how the world works. --Carl Sagan Science is a way of thinking much more than it is a body of knowledge. --Carl Sagan |
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#4 | |
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diyAudio Member
Join Date: Mar 2005
Location: Melbourne
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Quote:
Thanks
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