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#1 |
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diyAudio Member
Join Date: Dec 2006
Location: Florida, USA
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Hi, all. Can anyone explain or point me to a tutorial that shows a circuit that will power on a cmoy headphone amp when the headphones are plugged in? Thanks ahead of time.
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#2 | |
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diyAudio Member
Join Date: Dec 2006
Location: Florida, USA
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Quote:
Hmm, I've seen illustrations of phone jacks in the Mouser catalog with provision for disconnecting speakers when headphones are connected but none for power on/off. |
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#4 |
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diyAudio Member
Join Date: Dec 2006
Location: Florida, USA
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bump
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#5 |
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Magneto the Gravity Man
diyAudio Member
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Usually, the ground (sleeve) of the connector is used to switch either side of the battery depending on how the phones are conected)
Finding a switched 2.5 or 3.5mm socket may be the problem rather than how to connect it. Andy
__________________
If it ain't broke, break it !! Then fix it again. It's called DIY ! |
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#6 | |
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diyAudio Member
Join Date: Dec 2006
Location: Florida, USA
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Quote:
The cmoy uses a virrual ground for the headphone return so using the jack sleeve isn't an option. The switched phone jacks available at Mouser, DigiKey, etc are designed to interrupt the output to speakers. I thought I could design a circuit to use that but, alas, all my attempts have been in vain. I tried a jfet/bipolar transistor combination with appropriate resistors but that didn't work. Promising, but didn't work, it just screwed up the sound. There was no DC offset, it just made it sound bad, which means I didn't get something right. So instead of pursuing that further I thought I'd see if anyone else had any ideas. |
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#7 |
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diyAudio Member
Join Date: Sep 2005
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what about a relay?
use a switched socket to drive the relay coil. (it will mean that u need voltage on all the time though) but if u are close enough to plug the headphone in, surely it's nott too hard to flick a switch while you're there
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