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#1 |
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diyAudio Member
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What value of resistor (or a range of from 1 to 100 so that i can play with it) should i put to reduce the intensity by half of those 3mm, 2 volt LED- thanks
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na |
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#2 |
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diyAudio Member
Join Date: Nov 2007
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What is your supply voltage? Most just play around with some to get it the way they want. Also if your supply changes with load consider that. I don't know if 1v would give half light output, I doubt it.
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#3 |
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diyAudio Member
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Have not checked the voltage, but should be under 4v
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na |
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#4 |
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diyAudio Member
Join Date: Mar 2002
Location: Aveiro-Portugal
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Play with the current trough the LED.
10 mA is a good starting point...
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Jorge |
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#5 |
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diyAudio Member
Join Date: Nov 2007
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10ma is about 220 ohm. 5ma would be 430 according to a calculator on the net at 4v supply and 2v LED. So I guess I would get a 220 to 430+ ohm pot if possible, if the max current is 10ma. Or you know, put a 220 ohm on it and then a pot from 0 up to dim it. http://www.luxeonstar.com/resistor-calculator.php
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#6 |
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diyAudio Member
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Cant I just put a 500 ohm pot w/o a resistor ?
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na |
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#7 |
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diyAudio Member
Join Date: Mar 2002
Location: Aveiro-Portugal
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Put a 500 Ohms pot in series with a 100 Ohms resistor...
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Jorge |
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#8 |
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diyAudio Member
Join Date: Nov 2007
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Depending on max ma it can take, if you go lower ohms you could over power it.
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#9 | |
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diyAudio Member
Join Date: Mar 2002
Location: Aveiro-Portugal
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Quote:
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Jorge |
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