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#1 |
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diyAudio Member
Join Date: Jan 2012
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Hi,
Some newbie questions: I don't find any specs for my old 4" drivers and I need to measure the sensitivity since I'm going to replace them. The impedance is 4 ohm. I have a multimeter, a dB-meter and a 1 kHz sine wave sound source. If I have done my math correctly, I have to measure 2V with my multimeter to get 1W out from my driver. Two questions: 1. Should I measure DC voltage or AC voltage? 2. Should the driver be in its cabinet or outside while measuring? Thanks! |
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#2 |
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diyAudio Member
Join Date: Jan 2012
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Maybe it is 1.414V DC or 2V AC I should measure?
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#3 |
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diyAudio Member
Join Date: Apr 2010
Location: Jutland
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Hi t0mm1,
You need at Sound SPL meter, Lin, A or C for 1 kHz Always AC in Audio A ISO baffle but can't find a link |
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#4 |
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diyAudio Member
Join Date: Jan 2012
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#5 |
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diyAudio Member
Join Date: Jan 2012
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I measured 2V rms with my oscilloscope (since I think multimeters are designed for 50Hz)... and I only got about 50dB on 1 meter. I'm doing something really wrong I believe ;-)
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#6 |
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diyAudio Member
Join Date: Jul 2004
Location: Scottish Borders
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2Vrms on an oscilloscope?
How? Oscilloscope displays waveform. The waveform amplitude is generally read as a peak to peak voltage (Vpp). For a sinewave signal the Vpp to Vrms conversion factor is 2*sqrt(2) ~ 2.83. That 2.83 factor is equivalent to 9dB If you read 2Vpp from the scope then you need to add 9dB to your SPL reading to give a sensitivity @ 1kHz of ~59dB/2V @ your monitoring distance. Alternatively, increase your test signal from 2Vpp to 5.7Vpp Last edited by AndrewT; 6th April 2012 at 11:53 AM. |
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#7 | |
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diyAudio Member
Join Date: Jan 2012
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Quote:
So, having a 1kHz sine wave and measuring the line I adjusted the volume until the scope said 2V rms. Maybe I'm doing it wrong? |
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#8 |
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diyAudio Member
Join Date: Jul 2004
Location: Scottish Borders
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Wideband signal rather than a single frequency test signal.
But then you need and rms reading voltage meter to set the input signal. |
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#9 |
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diyAudio Member
Join Date: Jan 2012
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I think it might be better to let some professionals measure it instead... there are still too many factors that can ruin the results for a newbie like me ;-)
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#10 | |
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diyAudio Member
Join Date: Apr 2010
Location: Jutland
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Quote:
Watt = P = U * I Watt = P = R * I^2 You need at True RMS AC volt meter to atleast 1 kHz IEC Baffle and a SPL meter placed 1 meter in front of speaker To get the RMS out of a Peak 2 Peak SINUS value = a / SQR(2) : Where "a" is amplitude (peak value) http://en.wikipedia.org/wiki/Root_mean_square It should actually do it for you Last edited by d a o; 6th April 2012 at 01:58 PM. |
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