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#11 |
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diyAudio Member
Join Date: Aug 2002
Location: cdn
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Quote:
Hi Manfred, What range of resistors did you try for I/V conversion and what was the affect? Thanks, Ian |
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#12 | |
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diyAudio Member
Join Date: May 2002
Location: Munich/Bavaria
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Hi Ian,
Quote:
I have built an other unit for a friend which uses a 47R resistor, a third order passive L-C-L Bessel low pass and a single tube stage for amplification. This one sounds quite different but It is a completely different setup, not just a changed resistor value. In general there are two things to take into consideration: The D/A converter's output is protected by a pair of diodes against electrostatic discharge etc. These diodes will start to conduct when the output reaches about 600mV. We have to keep the I/U converting resistor low enough to prevent this from happening. In my case the D/A converter outputs max. +-1.25mA of current and the resistor is 22R. This means that the peek output voltage will be 22R*1.25mA=27.5mV. I guess this is a save bet. The other thing to consider is that I/U conversion done by a simple resistor will generate some 2nd order distortion products. This is because the output of the converter is not a real current source. The output resistance of the converter chip at max output level is Vref/(2*Iout_max). In the case of the PCM1704 this is 5V/2.5mA=2000R. At min output level all switches in the R2R ladder network are open and there is no current flowing at all. The output resistance is indefinitely high. Let's see what this means for the outout current: The min output current is Imin=-1.25mA. This is the current set by the internal bias current source. There is no current through the R2R network in this case. The max. output current is Vref divided by the sum of the resistances of the R2R network and the I/U conversion resistor less the bias current of 1.25mA: Imax=Vref/(2000R+22R)-1.25mA=1,2228mA This is 2,2% of deviation from the ideal of 1.25mA. The 2nd order distortion calculates as: K2(%) = 100 * (Imax+Imin)/2/(Imax+Imin) In our case:K2 = 100*(1.2228-1.25)/ 2/(1.2228+1.25) = 0,55% This is quite a bit of distortion but it is purely 2nd. order and there is a near linear relationship of distortion and level. The calculation was done under the assumption of max output level. If your CD is recorded at an average level of -20dB then there will also be about 20dB less distortion. In our case this means 0,055% of K2. Good enough for me. I hope this helps. I also hope I didn't make too many errors ![]() Regards Manfred |
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#13 |
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diyAudio Member
Join Date: Aug 2002
Location: cdn
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Hi Manfred,
Thanks for the detailed response, do you have documentation for the CDM12? Regards, Ian |
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#14 | |
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diyAudio Member
Join Date: May 2002
Location: Munich/Bavaria
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Hi Ian,
Quote:
I guess Holger Stein will send you the schematic if you ask nicely. Regards Manfred |
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#15 |
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Banned
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Hi Manfred,
May I ask what is the masterclock frequency the CDM12 uses? Last Friday I saw a expensive Euro 4000 costing transport using the CDM12 with the crystal hung on the microprocessor.
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#16 | ||
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diyAudio Member
Join Date: May 2002
Location: Munich/Bavaria
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Quote:
Quote:
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