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Old 22nd July 2005, 04:21 PM   #1
Adrian is offline Adrian  United Kingdom
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Default SPDIF driver - 74HCU04 output impedance?

Hi,

I'm looking at a simple capacitively coupled spdif driver using parallel 74hcu04s. In calculating the resistor values to get the correct ouput level and impedance is it worthwhile taking account of the 74hcu04 output imdedance - if so could someone suggest the value to use [can't find one on the relavent data sheets except a generic one from from Fairchild which suggests HC normal outputs are in the region of 40-50 ohms - http://www.fairchildsemi.com/an/AN/AN-393.pdf.]

Thanks.
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Old 22nd July 2005, 05:05 PM   #2
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40-50 ohms may be a bit high, but...............

Don't use parallel gates. Maybe if they are in separate packages, with ferrites to isolate them. Maybe.

But, yes, you do need to take into account the output Z of the chips. Something that a lot of alledged "high-end" designers never learned. Or if they did, neglected to take into account.

BTW.......I would measure it. A resistor and DVM will be enough to get you close.

Jocko
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Old 22nd July 2005, 07:12 PM   #3
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An opamp with feedback will have almost zero output impedance. Wait a minute Jocko, did I say f-e-e-d-b-a-c-k?
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Old 22nd July 2005, 07:52 PM   #4
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round 1!
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Old 22nd July 2005, 07:54 PM   #5
Adrian is offline Adrian  United Kingdom
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Thanks Jocko. Can you confirm what the problem with parallel gates is?

Adrian
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Old 22nd July 2005, 08:00 PM   #6
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Talking right place?

Quote:
Originally posted by Bricolo
round 1!

Bricolo, you are sure you are in the right place?
We don't have a gong here.
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Old 22nd July 2005, 11:15 PM   #7
Bricolo is offline Bricolo  France
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is it better now?

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Old 22nd July 2005, 11:24 PM   #8
Adrian is offline Adrian  United Kingdom
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Meanwhile, back at the original question - any info on why not to use parallel gates would be appreciated.
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Old 23rd July 2005, 12:05 AM   #9
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I didn't see him mention feedback. Did you? And how much open-loop gain do you think that one has???? Enough to lower the Z to zero ohms??

Anyway........if you have 6 inverters in one chip drawing six times the current, then the di/dt should be 6 times higher. Only one ground pin on the IC.......all that current in phase through it.....................you fill in the missing pieces.

Jocko
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Old 23rd July 2005, 09:23 PM   #10
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Quote:
Originally posted by Jocko Homo
I didn't see him mention feedback. Did you? And how much open-loop gain do you think that one has???? Enough to lower the Z to zero ohms??

Anyway........if you have 6 inverters in one chip drawing six times the current, then the di/dt should be 6 times higher. Only one ground pin on the IC.......all that current in phase through it.....................you fill in the missing pieces.

Jocko
Hi

Jocko is right both in terms of Zout as well as on advising on paralleling inverters. Additional note: Zout is only defined at the transfer of 0 to 1, in all other states the output impedance is high.

cheers
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