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Old 4th September 2012, 05:52 AM   #1
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Join Date: Jul 2012
Default Passive audio signal split to 3; is switch easiest way?

I would like to take an unbalanced input signal and create three outputs, each of which having an individual (attenuating) circuit, outputting to a 4 pole, three position rotary switch.

If I add another of the same switch to the input, I would then be able to create a split, but I would have to select the correct input to match the output (2 switches).

I would like to be able to have three independent split signals, without requiring power, and have them all be equal (so all I would need is the switch at the output). Hopefully I've articulated what I need well; is what I'm looking for possible? If so, what type of work is required (I may be okay with two switches, depending on the required skill level).

Last edited by HiFi1972; 4th September 2012 at 05:55 AM.
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Old 5th September 2012, 08:29 PM   #2
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Join Date: Jul 2012
Oookay, so I think I know why nobody responded to the above; I think I'm going to need to amplify each split (tried hooking things up the way I thought they'd work with a switch but the resistance from the other two affect the signal to all the "splits").

I know it's all about researching when it comes to DIY, and I've been looking at a lot of things online and have become confused about doing the above Passively, so I'm stuck and need to ask the following:

Am I right in saying that if I want to send each split to its own series of resistors for attenuation, that it can't be done passively? I need to amplify each split so that when attenuating one, it won't affect the other two? I just need someone with the knowledge to confirm my findings; it sounds like I need power and add a Distribution Amp to what I'm trying to build. The confusing thing about doing this passively is that I've found docs online saying each split can be done passively, with op amps and resistors, but I *think* the issue I've got is that I want to add different resistance to each of the splits, and I *think* I need power to do so, so a confirmation of these findings would be much appreciated (stuck on figuring out the possibilities!)
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Old 7th September 2012, 05:10 AM   #3
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Join Date: Jul 2003
Location: Dona paula, Goa
Put 4 series resistors at the output to ground. This will give u three different attenuated points. Connect a 2 pole 3way switch with poles in the middle. Now u have 3 different attenuated o/ps per channel.

Any resistor can be zero ohms.

Gajanan Phadte
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Old 7th September 2012, 06:04 AM   #4
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Join Date: Feb 2002
Location: Western Sydney
for each output, you need two resistors, the first connected from your input to the switch point. This will isolate the output from the other outputs. Then a resistor from the switch point to ground.
Impedance varies with frequency, use impedance plots of your drivers and make crossover calculations using the actual impedance of the driver at the crossover frequency
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Old 7th September 2012, 08:05 PM   #5
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Join Date: Jul 2012
Thanks! It had been a couple of days without replies, so I went and played around and got what I needed by hooking up the source to a 4 pole/3 pos switch (input to two poles), then another switch to select which split is active (this is all to feed a pair of VUs although I've only tested one channel). Each pos has a 2k preset pot, then another 500 ohm rheostat hooked up to gnd (for fine adjusting each split's resistance).

I noticed that if I put the rheostat on the gnd at the end of each split, before going to the second switch (which sends signal to the VUs) that the pot doesn't behave the same way; it doesn't show any attenuation until I break the signal (hit stop on transport). If I put the pot on the grounding pole to the meter, it then works the way I need it to (showing less & more resistance).
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