Slectable momentary or latching action - Page 2 - diyAudio
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Old 7th September 2011, 12:41 AM   #11
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Join Date: Aug 2011
I've kept at this and found I got it wrong above.
Momentary switch should be connected to the clock line, while the data line is connected to the "not Q" line.

Then, at a touch of the momentary, the flipflop will go from Q output, to Not Q.

Still... How can the flipflop keep the output high after the momentary witch is released? Doesn't there need to be another power connection directly to the flipflop somehow?

thanks
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Old 7th September 2011, 01:16 AM   #12
Enzo is offline Enzo  United States
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Location: Lansing, Michigan
Any basic logic tutorial will cover flip flops, whether CMOS or TTL. The configurations will be the same, just the part numbers and voltages will differ.

All logic ICs need power and ground connections. SOme pins may be also conected directly to V+ or ground. And you may see pins connected to other pins, for example, the /Q conected back to the data pin. Now every time the clock advances, the Q and /Q will toggle, putting the opposite state on the data pin.

The whole point of flip flops is that they only change state when you clock them. Or when set and reset pins are enabled. And even then, rising edge and falling edge matter. They will latch into the state you put them
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Old 7th September 2011, 01:51 AM   #13
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Almost all of the tutorials and such that I encountered used a block diagram for the flipflop. the diagram would only show 4 lines, data, clock, Q, not Q.

They didn't show the V+ or gnd.

Duh, that's what I was missing. thanks.
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Old 8th September 2011, 01:03 AM   #14
Enzo is offline Enzo  United States
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The power connections are usually assumed. SOme drawers will add them to one of the gates in the IC, but in logic, every chip has them, so they don;t clutter the drawing with them.
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