If output going to clip , will it burn the mosfet ??

[titanchen68]

I use Rin = 2.2k and R(feedback)= 62K, gain ~= 30v/v.
+V =56v and -V = -56v.
If the input signal amplitude =2v , and output will higher than 56v.
It get clip , will it burn the output mosfet ???

1.
My triangle wave = 7Vpp , so i limit the input signal lower than 2v.
Avoid going to saturation.
But it will not have the maxmun power output.
so , i increase the feedback resistor to increase the whole gainer.
Is that right ??

2.
If the input signal have got clip, the output sill get clip.
will it also burn out the output mosfet ??

[richie00boy]

Class-d is achieved by driving the MOSFET to 'clipping' -- that is how they are so efficient. If you hadn't realised that maybe you ought to try something simpler to start with.

[titanchen68]

Yes , you right !! I got some wrong concept!!

I should ask in other way.
In normal , the mosfet work duty cycle is 50%.
If duty cycle going to 100% , what will happen ??
Or it will not happen forever??

If input signal going to saturate , higher than pre-amp's +vcc.
The input signal looks like square.
so , the output signal of amp will also like a square wave right??
And will it get someing wrong ???
Or damege something else ???

[richie00boy]

Because the MOSFET will always be saturated or totally off, very little power will be dissipated by it. As long as the output is not shorted everything should be fine. If your MOSFET is rated well enough it may even survive a short term short.

[titanchen68]

OK , thanks a lot !!
so , even the input audio signal amplitude higher than triangle wave amplitude , it will be fine right ?? as long as my mosfet can driver the current ??

Because i always burned out the mosfet , when i trun the volumn to the higheset. and driver in two speakers.

Thanks again.!!

[classd4sure]

It _should_ survive clipping, yes.

One factor in play is how you drive the high side mosfet. If for instance you use a dual N channel output stage with the upper driver supplied by a bootstrap circuit, drive it into clipping and the bootstrap cap is too small to maintain charge for that extra period of time, the gate - source voltage will fall and bring the mosfet into linear conduction, dissipating very high power and very likely cook, taking out the speaker, and the other mosfet when it next tries to turn on.

For example, 1uF is about 200 times too small.

Good luck.

[titanchen68]

I'm sorry , I don't understand that "1uF is about 200 times too small"
now , i use 470nF cap be the bootstrape cap.
It that too small?

[classd4sure]

That's pathetically small. Try more like 100uF.... 220uF would be best.

[titanchen68]

oh?? should be using 100uF ??? do you mean C25 on my schematic??
my schematic used 1uF // 104 be the bootstrape cap yet.
But the member "SSassen" told me should use 470nF be the bootstrape cap.
He said that "the bootstrap capacitor should be between 0.1 ~ 0.33uF, yours is too large.
I use 1uF//104 yet.... but he said too large.
And when i use 1uF//104 , i can not turn on the amp normally.
The output of the error_amp going to saturate.
When i change c25 to 470nF, it work find.

[Pierre]

Sorry but experience makes me disagree with ClassD4sure also.

1uF is optimum. I have played with a lot of versions of my class-D amp, based on a IR2113 chip with bootstrap cap. I started with 47uF, but it produced a very audible "click" at turn on.
I reduced it and found that 1uF produces almost no audible "click" while still maintaining full charge even clipping with a 10Hz signal.

You can have a look at the IR app.notes and find that for typical applications (200-400KHz, usual mosfets, 12-15V Vcc, etc), you theoretically need less than 100nF, although it is good to have at least 10 times that.