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#1 |
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diyAudio Member
Join Date: May 2003
Location: AARHUS. DK
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If an SMPS is operated in continuous mode the current in the output induktor will be a DC-current with an small superimposed AC-ripple.
When calculating the loss in the induktor I would guess that I should add the loss for the DC-current and the loss for the AC-ripple? The DC-loss is a function of the DC-resistance and this resistance is usually very small. The AC-loss is a function af eddy-current-resistance in the inductor and this "resistance" is many times larger. My problem is: When calculating the loss, do I use formula 1) or 2) 1): Ploss = Rdc*Idc^2 + Reddy*Iac^2 2): Ploss = Rdc*(Idc+Iac)^2 + Reddy*(Idc+Iac)^2 Please help me, and please do it now! -I have an exam in 4 hours and 10 minutes.... Troels
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#2 |
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diyAudio Member
Join Date: May 2002
Location: Switzerland
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Hi Troels
From a quick shot at it I'd say it is: 3): Ploss = Rdc * (Idc^2 + Iac^2) + Reddy * Iac^2 But don't sue me if it is wrong. Regards Charles |
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#3 |
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diyAudio Member
Join Date: May 2003
Location: AARHUS. DK
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I figured it out. BTW my grade was 11 (0 to 13 scale)!
Troels
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