is it possible to run a sub channel through one of these?

[gafhenderson]

sorry to bombard the forums with silly questions.

4*100W TK2050 TP2050 D-class Audio Amplifier Board | eBay

4x100watts.

is it possible to use 2 of the channels for speakers (high), then use the remaining 2 double up to drive a subwoofer channel @200watts?

if it is possible how do you hook the subs up to the device?

thanks for your help.

[Osvaldo de Banfield]

keep in mind that bridging amp´s multiply by four the power, so in this case a 100W stereo, when bridge wired will be 400W, so be sure the speaker can handle such a power!!!

[gafhenderson]

Originally Posted by Osvaldo de Banfield

keep in mind that bridging amp´s multiply by four the power, so in this case a 100W stereo, when bridge wired will be 400W, so be sure the speaker can handle such a power!!!

thanks for the reply,

i'm not sure i understand you completely.

so for this amp i was planning on using 2 of the channels for my main speakers, does this mean instead of 100watts per speaker it will be 200watts per speaker? 200watts per speaker is the limit of their power handling.

the subs have a high power handling so 400watts would be ok.

[sreten]

Hi,

I think each channel is already bridged and further bridging is not possible.
That is each channel is 2 x 50W 2 ohm bridged for 100W 4 ohm.

Keep all negatives separate, they are not common.

Easiest way to use two channels for a sub is the sub has 2 x 4 ohm drivers,
(side mounting for force cancellation), or use a dual coil 2 x 4 ohm driver.
No bridging, just send the same input to both channels.

rgds, sreten.

[Osvaldo de Banfield]

Originally Posted by sreten

Hi,

I think each channel is already bridged and further bridging is not possible.
That is each channel is 2 x 50W 2 ohm bridged for 100W 4 ohm.

He talks about 4 * 100W channel, if I am not confused. So I understand, he want to use 2 * 100 separately, and the other two bridged. Once again, bridge multiply by 4 the total output power since power in same load is voltage squared, so double voltage is 4 times power.

[lost eden]

All of the 2000/2050 amps from Sure Electronics are already internally bridged so the outputs cannot be bridged. This information should be in the manual (it certainly is for the 2x 100W board), which you can find on Sure's site.

keep in mind that bridging amp´s multiply by four the power, so in this case a 100W stereo, when bridge wired will be 400W

The '4x myth', whilst not strictly a myth, is definitely misleading when ti comes to actual performance. A more accurate estimation of real-world performance is to half the output impedance & double the power output that the amp produces at that impedance, as when driving (for example) an 8R bridge load the amp essentially sees a 4R load. It is unrealistic to expect an amp to produce much more into an 8R bridge than it can (in total) into a 4R stereo load.

[sreten]

Originally Posted by Osvaldo de Banfield

He talks about 4 * 100W channel, if I am not confused. So I understand, he want to use
2 * 100 separately, and the other two bridged. Once again, bridge multiply by 4 the total
output power since power in same load is voltage squared, so double voltage is 4 times power.

Hi,

Your just repeating a niave "fact" that is not often true and does not apply.

Once again, you can't bridge channels that are internally bridged.

For 4 x 100W 4 ohm watt normal amplifiers, you can bridge two of them
and use a 8 ohm subwoofer for 200W output on the bridged channel.

You cannot get 400W out of the bridged channel unless the amplifiers
can produce 200W per channel into 2 ohms in unbridged mode, so
your statement is not generally true, bridging is not 4 times power.

I've stated how to "hook up the subs to the device" in question.

rgds, sreten,.

[Osvaldo de Banfield]

I don´t know how internally this stuff works. I´m just taking since the output terminals. The poster don´t mention if internally his apparatus is bridged or not, and I don´t know too much about commercial equipment. Sorry if my comments are wrong for this particular case, but every time you double voltage across a fixed resistance, power is 4 times greater. It´s mathematics, don´t a myth...

[sreten]

Originally Posted by Osvaldo de Banfield

I don´t know how internally this stuff works. I´m just taking since the output
terminals. The poster don´t mention if internally his apparatus is bridged or not,
and I don´t know too much about commercial equipment. Sorry if my comments
are wrong for this particular case, but every time you double voltage across a
fixed resistance, power is 4 times greater. It´s mathematics, don´t a myth...

Hi,

You know the basic "ideal" maths, and nothing else it seems.

IMO don't give practical advice unless you know your onions.

Seems pointless explaining further, pointers are alluded to above.

rgds, sreten.

It is a myth, consequently often very badly applied to a practical situation.

[gafhenderson]

Originally Posted by sreten

Hi,

Your just repeating a niave "fact" that is not often true and does not apply.

Once again, you can't bridge channels that are internally bridged.

For 4 x 100W 4 ohm watt normal amplifiers, you can bridge two of them
and use a 8 ohm subwoofer for 200W output on the bridged channel.

You cannot get 400W out of the bridged channel unless the amplifiers
can produce 200W per channel into 2 ohms in unbridged mode, so
your statement is not generally true, bridging is not 4 times power.

I've stated how to "hook up the subs to the device" in question.

rgds, sreten,.

thanks for the reply.

so in very simple terms i cannot do this.

if this is not possible can i simply use 2 sub-woofers at 100watt each?