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#1 |
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diyAudio Member
Join Date: Feb 2006
Location: Belgrade
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I built my first class D amp. It's a full bridge, single supply, based on LT1162 bridge driver. It sounds great, but I have some questions about output filter. Currently, my output coils are wounded on separate cores ( core EF25, 1mm air gap ), but I saw that they can be wound on same core.
1. one core is advantage ( smaller PCB, costs... ), but are there some disadvantages ? 2. how to calculate C3, C4, C5 ? thanks. |
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#2 |
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diyAudio Member
Join Date: Feb 2006
Location: Belgrade
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Somebody ?
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#3 |
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diyAudio Member
Join Date: May 2007
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C3 = 1/2 C2 (C2 from the left picture
C4=C5= 2 * C3 (C3 from the right picture)
__________________
Houston, we have a problem! |
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#4 |
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diyAudio Member
Join Date: Feb 2006
Location: Belgrade
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Are you sure ( C4=C5=2*C3=C2 ) ? I saw a few schematics and always is C3>C4.
What about 1st question ? |
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#5 |
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diyAudio Member
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First, when the coils are wound on the same core you only need half the windings for each coil, compared to winding on two separate cores.
Second, you don't need C4 and C5. C3 should be half that of C1. Thirdly, remember that when calculating L1/C1, you should set Rload to half that of the seaker, in your example 4 ohm due to the ballanced mode. |
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#6 |
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diyAudio Member
Join Date: Feb 2004
Location: Anonymityville
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__________________
"If you don't like funerals don't kick sand in ninja's face." |
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#7 | ||
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diyAudio Member
Join Date: Feb 2006
Location: Belgrade
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Thanks for all.
Quote:
Quote:
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#8 |
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diyAudio Member
Join Date: Dec 2003
Location: Nottingham UK
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If you only have a cap across the speaker (and not also a cap from each side of the speaker to ground), then any common-mode noise produced by the amp will radiate and give you big EMC problems. It is ALWAYS wise to fit C4, C5 to help filter out common-mode noise. (I've got caught by this myself before).
Believe me, there will be C-M noise at RF produced by the switching! |
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#9 |
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diyAudio Member
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This is of course true. I use these my self in my bridged design. These only have to be like 10% of C3 in value. As you say Ouroboros they are ther to reduce commonmode noise, but remember that they will add to the filtering effect.
So if you have C3 = 1uf and C4=C5=100nF then the resulting "C3" will be 1,05uF (stil pretty close to 1uF though )
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#10 |
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diyAudio Member
Join Date: Sep 2007
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I have a very similar issue, but this forum isn't letting me start a new thread.
So I apologize, I plan on hijacking this thread if it won't let me post it. |
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