Low frequency cutoff calculation for Noninverted. - diyAudio
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Old 8th August 2006, 08:52 AM   #1
5150ed is offline 5150ed  Thailand
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Default Low frequency cutoff calculation for Noninverted.

Can anybody explain how to calculate the lowfrequency cutoff of input capasitor for inverted GC?

I commonly found the 4.7mf input cap for noninverted schematic but I already a pair of 1mf of very good cap, is the value is too low?
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Old 8th August 2006, 08:58 AM   #2
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159155/(resistance * frequency)
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Old 9th August 2006, 02:12 AM   #3
5150ed is offline 5150ed  Thailand
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hmmmm..... I do not quite get it.

Do u mean? 159155/(resistance * frequency)= capasitor value
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Old 9th August 2006, 03:33 AM   #4
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The low frequency cuttoff is 4Hz, so you can calculate the DC blocking capacitor by below formula

Ci = 1/(2*PI*f*Ri)

If your input impedance is 22K Ohm Ci should be 2.2uF by the formula.
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Old 9th August 2006, 03:36 AM   #5
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159155 = 1000000/(2*pi)

The formula unit is microfarad.
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Old 9th August 2006, 03:57 AM   #6
5150ed is offline 5150ed  Thailand
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Thank a lot.

But what is PI???
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Old 9th August 2006, 07:32 AM   #7
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Old 9th August 2006, 10:05 AM   #8
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I tried both formulas or formuli. I got 1.80uf.
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Old 9th August 2006, 12:43 PM   #9
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Default Units of measurement

Quote:
Originally posted by 5150ed
Thank a lot.

But what is PI???
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Old 9th August 2006, 02:04 PM   #10
Sherman is offline Sherman  United States
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Quote:
Originally posted by 5150ed
Thank a lot.

But what is PI???

Technically it is the ratio of the circumference of a circle to its diameter. It is an 'irrational number', when the division is carried out it never ends and never repeats.

For all practical purposes in these formulas just use 3.1416.
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