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#1 | |
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diyAudio Member
Join Date: Jun 2006
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I've been reading up on Ohm's Law, and i made up some equasions here for an amp / psu i'd like to make, im not sure how exact the math has to be, so i figured i'd run it past you folks, maybe you can give me a hand
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#2 |
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diyAudio Member
Join Date: Nov 2005
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Looks good... I don't understand why you have R listed in your power supply calc's.
Use I for current in the future... not C. C is used for capacitance. And don't expect to pull 20 Amps from a wall outlet. If you need that much power... change your equipment to 240 V... like a dryer or stove.
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#3 |
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diyAudio Member
Join Date: Jun 2006
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How many amps should i pull from the outlet? 4 - 5?
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#4 |
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diyAudio Member
Join Date: Nov 2005
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It might help to know what you are doing?
If your power supply is putting out 243 Watts, it is probably requiring 243 / .95 = 256 Watts at its input. This assumes 95% efficiency... could be lower like 85 - 90% If 256 Watts were going into your supply; what would the current be?
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#5 |
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diyAudio Member
Join Date: Jun 2006
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2.13 Amps?
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#6 |
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diyAudio Member
Join Date: Nov 2005
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Yes!
It is important to understand that the wall socket doesn't just cram 20 Amps into anything you plug in. The input to the power supply has a resistance (not really a resistor) that determines what anount of current flows. With what you know... what is the "effective input resistance" of your power supply?
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#7 |
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diyAudio Member
Join Date: May 2006
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Home electrical circuit usually put out either 15 or 20 amps (if we are talking US here) . Unless you are building a 1500+ watt amplifier, however that's not what you should be worried about.
Try going backwards from your amp wattage to determine what size transformer you need. |
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#8 |
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diyAudio Member
Join Date: Jun 2006
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Ok, using the following variables
P = 256 Watts (What im drawing from my outlet) E = 120 Volts (What im drawing from my outlet) Now that i have 2 Set variables, i can now find the other 2 I (Current) R (Resistance) R = (E * E) / P R = 260.86 Ohms I = V / R I = 0.46 Amps So my effective input resistance is 206.86 Ohms?
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#9 | |
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diyAudio Member
Join Date: Jun 2006
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Quote:
-------------------- edit -------------------- Correct me if im wrong, but i should have the output of the powersupply give more power (Watts) than what my Amp calls for right? I know for computers, you should always have more wattage than your computer draws. Thanks!
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#10 |
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diyAudio Member
Join Date: Nov 2005
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Nope,
You are drawing 2.13 Amps... remember? R = V / I = 120 / 2.13 = 56.3 Ohms |
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