Amp on TDA 7294

maris24 · 14th January 2005, 04:48 PM

So the amp is on TDA 7294 and the problem is that the maximum output is only 30 Watts on 4 Ohms, +/- 27 Volts BUT in user manuals and instructions there are given two times more Watts. So If enyone knows where is the problem or how to solve that please leave the message.

Thanks

Bricolo · 14th January 2005, 05:22 PM

where did you see this 30W limitation?

Mine runs on 25V (DC) and outputs approx. 60W in 4 ohm

maris24 · 16th January 2005, 07:21 PM

Mine is 15 V (AC), 4 Ohms

P=U^2/2R

So 15x15=225/(2x4)=28 W

Bricolo · 16th January 2005, 07:30 PM

P=U²/R

victorio · 17th November 2006, 10:11 AM

P= (V^2)/(2R) is only true when you are getting the peak value of the voltage. I dont believe thats the case, so use the formula Bricolo gave, what gives you almost 60 W power.

14th January 2005, 04:48 PM	#1
maris24 diyAudio Member Join Date: Jan 2005 Location: Riga	Amp on TDA 7294 So the amp is on TDA 7294 and the problem is that the maximum output is only 30 Watts on 4 Ohms, +/- 27 Volts BUT in user manuals and instructions there are given two times more Watts. So If enyone knows where is the problem or how to solve that please leave the message. Thanks

14th January 2005, 05:22 PM	#2
Bricolo diyAudio Member Join Date: Nov 2002 Location: Grenoble, FR	where did you see this 30W limitation? Mine runs on 25V (DC) and outputs approx. 60W in 4 ohm __________________ Just remember: in theory there's no difference between theory and practice. But in practice it usually is quite a bit difference... Bob Pease

16th January 2005, 07:30 PM	#4
Bricolo diyAudio Member Join Date: Nov 2002 Location: Grenoble, FR	P=U²/R __________________ Just remember: in theory there's no difference between theory and practice. But in practice it usually is quite a bit difference... Bob Pease

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16th January 2005, 07:21 PM	#3
maris24 diyAudio Member Join Date: Jan 2005 Location: Riga	Mine is 15 V (AC), 4 Ohms P=U^2/2R So 15x15=225/(2x4)=28 W

17th November 2006, 10:11 AM	#5
victorio diyAudio Member Join Date: Nov 2006	P= (V^2)/(2R) is only true when you are getting the peak value of the voltage. I dont believe thats the case, so use the formula Bricolo gave, what gives you almost 60 W power.

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