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#1 |
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diyAudio Member
Join Date: Apr 2004
Location: Singapore
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hi all
according to the chipamp lm4780 kit, the parts are as follows: LM4780 Dual Mono Kit Contents 1 PCB set, consisting of 2 amplifier and 2 rectifier boards. 2 LM4780 6 22 kohm 0.5w compact metal film resistors 4 2 kohm 0.5w compact metal film resistors 4 680 ohm 0.5w compact metal film resistors 2 10 kohm 0.5w compact metal film resistors (mute) 4 0.1 ohm 3w Dale LVR3 power resistors (output) 4 2.7 ohm 2w Panasonic metal film resistors (zobel) 4 0.1 uf BC polypropylene cap (zobel) 4 1500 uF 50v Panasonic FC Capacitors 16 MUR860 On Semiconductor Diodes 4 10 uF Panasonic FC Capacitors but on the pcb i'm not sure which goes where as there is no documentation yet. can someone confirm the below? i gather the following information from other threads: R1 = 22k (feedback resistors) R2 = 22k (feedback resistors) R3 = 1k or 680R (for more gain) R4 = 22k R5 = 1k or 680R (for more gain) R6 = 1k or 220R (series input resistors) R7 = 1k or 220R (series input resistors) R8 = 0.1R (output) R9 = 0.1R (output) Cz1 and Cz2 seems to be the zobel cap. the holes parallel to Cz1 and Cz2 seems to be the zobel resistors. C1 and C2 are the 10uF bypass caps or BG 4.7uF N caps. thanks garbage btw, i've got my boards. ![]()
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#2 |
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diyAudio Member
Join Date: Apr 2004
Location: Singapore
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#3 |
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diyAudio Member
Join Date: Dec 2001
Location: Pittsburgh, PA, USA
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You can't measure such low impedances with a standard multimeter. You should run a known current through it and measure the voltage instead.
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#4 | |
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Banned
Join Date: Mar 2003
Location: Lisbon, Portugal
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Quote:
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#5 |
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diyAudio Member
Join Date: Dec 2001
Location: Pittsburgh, PA, USA
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What is this "analog" you speak of, good sir?
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#6 | |
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Banned
Join Date: Mar 2003
Location: Lisbon, Portugal
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Quote:
http://www.gmc-instruments.com/engli...metrahit1a.htm |
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#7 |
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diyAudio Member
Join Date: Dec 2001
Location: Pittsburgh, PA, USA
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I was just joking
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#8 |
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diyAudio Member
Join Date: Sep 2003
Location: Nootdorp, Netherlands
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Forget it Carlosfm, you can't measure such low resistances acurate with a standard multimeter (digital or analog) , only with very expensive multimeters, special mili-ohm meters or the methode posted by trioth.
Please escuse my bad knowlegde of this language.
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#9 | ||
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Banned
Join Date: Mar 2003
Location: Lisbon, Portugal
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Quote:
Quote:
It's one of the only things that make me sometimes use my old analog multimeter. Check the link I posted, you can see this feature: "Resistance measurement: 1 Ohm .. 1 MOhm (4 ranges)" It just measures to 1MOhm, while my DMM measures to 200MOhm. But it's in the low end of the scale that analog MM has it's advantages. |
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#10 |
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diyAudio Member
Join Date: Sep 2003
Location: Nootdorp, Netherlands
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carlosfm, for what i read in the documentation, resistance-measurements are with intern battery from 1,5 DC Volt.
Measuring 0,1 Ohm (thats what the post form Garbage is about) : I = 1,5V/0,1 Ohm = 15A!!! P= 22,5W!!! The documentation says max. current for measure Ohms is 83 mA. Or didn't i read the documentation well (possible, becouse i am a Dutch speaking person with only little knowledge of other languages, sorry for that) Please your opinion??
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