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#1 |
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diyAudio Member
Join Date: Feb 2004
Location: Mexico City
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I've built two gainclones based on briangt boards i've used 20k stepped attenuators with great success.
I'm about to build another as a gift and wan't to use the much cheaper RS 100k pot instead. The manual shows the connection diagram but also mentions a "shunt" resistor. What value would the resistor be for a 100k pot? How do I connect it? Thanks a lot |
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#2 |
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Banned
Join Date: Mar 2003
Location: Lisbon, Portugal
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You can't find cheap 20k, 22k or 25k log pots?
Actually this is the right value for a pot on that NI amp. You will have lower DC-offset on the output. The 22k shunt resistor on the board should be changed for 220k. Actually, it will not be a shunt anymore, as you can see, I'm suggesting a value of around 10x de value of the pot. It's only for protection. The shunt resistor, not being a shunt anymore, will have less impact on the sound quality. Yes, you don't need to use expensive resistors, just the right value ones.
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#3 |
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diyAudio Member
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The combinaton of your pot ( at max position) and shunt resistor should be more or less equal to fedback resistor to avoid excessive DC offset values.
22k shunt resistor works well in most cases (with any pot value). Since in this case the value of a shunt resistor is lower than the value of your pot, it's influence might be greater on the sound. In case you use some more exotic stuff (like Caddock for instance), it's a good thing.
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