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#1 |
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diyAudio Member
Join Date: Oct 2011
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Dear all, I have several questions concerning the potentiometer/attenuator used as volume control.
1. The attached diagram is ok or do you suggest better topology? 2. If R1=1k, R2=20k, R3=20k (=R2 for minimal DC offset), R4=1k, what are recommended values for potentiometer P and why? 3. What’s the best way to have constant input impedance if P is in parallel with R3 ? |
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#2 |
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diyAudio Member
Join Date: Jun 2011
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Why not use the R3 as the potentiometer (20k)?
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#3 |
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diyAudio Member
Join Date: Jul 2004
Location: Scottish Borders
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if Pot is parallel with R3 then a ratio of >=10:1 gives a substantially constant input impedance.
eg. your Rin = 20k. 1/10 of that is 2k. If the output impedance of the Source is <=2k then you are in the ballpark A 8k pot has a maximum output impedance of ~2k. The closest but lower value pot to use is 5k. 5k can be driven by any headphone output from any source. Some line level outputs from rubbish equipment may struggle to drive 5k and the cable joining them. If you decide to use a 10k pot then I'd suggest you use a Rin >= 25k and preferably 47k or 51k. Post2's suggestion of a 20k pot for a Rin=20k is asking for very non constant input impedance. |
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#4 | |
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diyAudio Member
Join Date: Oct 2011
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Quote:
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#5 |
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diyAudio Member
Join Date: Jul 2004
Location: Scottish Borders
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That would be the complete opposite to what I led you through as an example.
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#6 |
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diyAudio Member
Join Date: Jun 2011
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Ah... Sorry...
I was simply trying to suggest what can be seen for example in the LM3886 data sheet... |
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#7 |
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diyAudio Member
Join Date: Jul 2004
Location: Scottish Borders
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work it out.
At full volume the Source sees POT//Rin At minimum volume the Source sees POT. |
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#8 |
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diyAudio Member
Join Date: Oct 2011
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#9 |
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diyAudio Member
Join Date: Jul 2004
Location: Scottish Borders
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sort of.
But that was not what you asked. You asked about near constant input impedance and I gave you a rule of thumb that gives near constant input impedance. If you do have varying input impedance then any preceding filters will have varying filter turn-over frequency. |
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#10 | |
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diyAudio Member
Join Date: Oct 2011
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Quote:
If in the same setup as in first diagram the logarithmic potentiometer P=50k or P=100k is in parallel with R3=20k, will be the resulting curve still logarithmic? If not, what would be the solution still using a passive potentiometer or attenuator? |
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