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#1 |
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diyAudio Member
Join Date: Jan 2012
Location: Rio de Janeiro
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I would like to find out TPA6120 built in the datasheet reference schematic "Single-Ended Input With a Noninverting Gain of -1 V/V" with Rl = 1k and Rf = 1k.
It says the input resistance of TPA6120 is 300k, however, I am a bit confused because input resistance and input impedance are clearly different concepts. So I figured this should not be the input impedance of this chip. Also, in my past experience, I figure the input impedance of this stage is quite low. Has anyone measured this or know an equation to come up with this? Last edited by Mateo Jun; 4th February 2012 at 12:52 AM. |
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#2 |
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diyAudio Member
Join Date: Apr 2008
Location: Carlisle, England
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If the audio goes in on the + input then the input impedance is 300K.
If the audio goes in on the - input it will be the input resistor to the - input.
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http://www.murtonpikesystems.co.uk PCBCAD40 pcb design software. |
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#3 |
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diyAudio Member
Join Date: Jan 2012
Location: Rio de Janeiro
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#4 |
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diyAudio Member
Join Date: Jul 2004
Location: Scottish Borders
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Using the 1k & 1k around the inverting amp, you will probably need a source impedance <=51r.
Aiming for ~10r might be better.
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regards Andrew T. |
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#5 |
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diyAudio Member
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The data sheet says it's a current feedback (CFA) type opamp so that is one reason why the resistor values are low. You need to keep to that and use a suitable driver before this device.
The inverting and non inverting input impedances are very very different on a CFA amp as far as I know. Non inverting input is normally high impedance and inverting is low impedance. Looks a very interesting device though
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------------------------------------------------------- A simulation free zone. Design it, build it, test it. |
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#6 |
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Audio Engineer
diyAudio Member
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If you haven't used current feedback amplifiers before, be sure to take notice of the feedback resistor value requirements. If you have reasonable math and some electronics this is a good description. You can treat the positive input much like you would a voltage amplifier. The negative input needs the correct resistance feedback resistor to remain stable and you must ensure parasitic capacitance is minimised. So it it's on a plane you may need a guard ring to isolate the input from the plane capacitance or to relive the plane in that region.
http://cas.ee.ic.ac.uk/people/dario/...cf-sloa080.pdf Regards, Andy |
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