AMP 12V 8 ohms output power 30W and very simple

kasimo · 1st January 2012, 01:59 PM

with 12 V and a resistance of 8 ohms, the theoretical max should be:
P = (12 * 12) / 8 = 18 W

SO if If it is used 18v instead of 12v you will be
P = (18 * 18) / 8 = 40.5 W ?

djoffe · 1st January 2012, 07:02 PM

Your formula is correct if your assume rail to rail swings and square waves.
However, it is more typical to rate the output power with a sine wave. In that case the powers will be half of what you quote.

kasimo · 2nd January 2012, 06:12 PM

This is good, but I want to I want what is the maximum of effort

Or there is a problem cooling the transistor

1st January 2012, 01:59 PM	#1
kasimo diyAudio Member Join Date: Dec 2011	AMP 12V 8 ohms output power 30W and very simple with 12 V and a resistance of 8 ohms, the theoretical max should be: P = (12 * 12) / 8 = 18 W SO if If it is used 18v instead of 12v you will be P = (18 * 18) / 8 = 40.5 W ?

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1st January 2012, 07:02 PM	#2
djoffe diyAudio Member Join Date: Oct 2008	Your formula is correct if your assume rail to rail swings and square waves. However, it is more typical to rate the output power with a sine wave. In that case the powers will be half of what you quote.

2nd January 2012, 06:12 PM	#3
kasimo diyAudio Member Join Date: Dec 2011	This is good, but I want to I want what is the maximum of effort Or there is a problem cooling the transistor

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