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Old 12th September 2011, 10:48 PM   #1
epilot is offline epilot  United States
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Default Max. supplies ) = ± (Vopeak + Vod)(1 + regulation)(1.1).

Hi guys,

Regarding the equation #7 in the datasheet of the LM3886 power amplifier(page #20):
Max. supplies ) = ± (Vopeak + Vod)(1 + regulation)(1.1).
Several lines below that equation there is an example called "DESIGN A 40W/4Ω AUDIO AMPLIFIER".
Sorry if it is a crazy question but I do not know how they found "supply required" ie +-21v and of course the supply voltage of ±26.6V using Equation (7)?

What is Vod really? is it the 4V drop out voltage of the IC?

thanks for any help.

Last edited by epilot; 12th September 2011 at 10:50 PM.
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Old 12th September 2011, 10:52 PM   #2
epilot is offline epilot  United States
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furthermore what do they mean by "input sensitivity" just below the equaetion #7 at the datasheet? are they mean the gain of the amplifier?

Thanks
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Old 12th September 2011, 11:07 PM   #3
epilot is offline epilot  United States
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I guess that in the example they replaced the (Vopeak + Vod) with the supply required i.e ±21.0V.
If so why they told that dropout voltage is 4V for LM3886, while they considered it as:
(Vopeak + Vod)=(17.9+3.1)=21V?
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Old 13th September 2011, 09:29 AM   #4
AndrewT is offline AndrewT  Scotland
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Could Vod be something to do with the voltage drop across the rectifier diodes?

The (1.1) looks like a correction for mains supply overvoltage, i.e. nominal mains voltage + 10%
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Old 13th September 2011, 06:32 PM   #5
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The chapter before the equation gives the answer.

Vod = LM3886's dropout voltage calculated from the Clipping vs Supply Voltage graphs on page 10. It is 4 Volt typical.

1.1 = as Andrew assumes the correction for mains overvoltage according to IEC specs.
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Old 13th September 2011, 07:00 PM   #6
epilot is offline epilot  United States
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Quote:
Originally Posted by pacificblue View Post
The chapter before the equation gives the answer.

Vod = LM3886's dropout voltage calculated from the Clipping vs Supply Voltage graphs on page 10. It is 4 Volt typical.

1.1 = as Andrew assumes the correction for mains overvoltage according to IEC specs.
Thanks.
Yea, I honestly do know that the dropout voltage regarding the datasheet is 4V, But plz calculte the and solve the exam in the datasheet as I stateed it in my first post and you will get a wrong respond! I want to know how they got a supply required of ±21.0V while Vopeak was 17.9V in the example of page 20??!

What do you mean by mains overvolatge really?

Thanks
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Old 13th September 2011, 09:31 PM   #7
epilot is offline epilot  United States
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Yea. I noticed what they mean by "1.1". It is due to 10% increasement in supply voltage.

Now the main question is that why they in the examination of page #20 used a droput voltage of 3.1V instead of 4V????
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Old 14th September 2011, 06:28 PM   #8
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Because the dropout voltage depends on the output current. 3,1 V is the dropout voltage at the maximum output of the 40 W amp. At the bottom of page 10 there are diagrams that show the clipping = dropout voltage. For a supply voltage of 21 V, Vee is 3,1 V.
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